Question

如何使用Google People API获取登录用户的电子邮件地址？

我正在尝试检索已登录用户的电子邮件地址，以便我可以将其与我应用中的数据进行比较。我已尝试过各种方法来获取它，但下面的代码只是返回undefined。

      function makeApiCall() {
    gapi.client.people.people.get({
      'resourceName': 'people/me',
      'requestMask.includeField': 'person.names,person.emailAddresses'
    }).then(function(resp) {
      var name = resp.result.names[0].givenName;
      var email = resp.result.emailAddresses[0].emailAddress;
      authorizeButton.insertAdjacentHTML('beforebegin', '<small rel="' + email + '">Logged in as ' + name + '</small>');
    });
  }

将其更改为var email = resp.result.emailAddresses[0];会产生[object Object]。

我也尝试使用JSON.parse()，但收到以下错误：

Uncaught SyntaxError: Unexpected token u in JSON at position 0
at JSON.parse (<anonymous>)
at (index):285
at h.r2 (cb=gapi.loaded_0:119)
at xs (cb=gapi.loaded_0:122)
at Wq (cb=gapi.loaded_0:122)
at _.C.uea (cb=gapi.loaded_0:121)
at Ap (cb=gapi.loaded_0:115)
at <anonymous>

我也尝试了this other unanswered question about the Google People API中的方法。

Answer 1

请做一次

using System.Xml.Serialization;
using System.IO;

public static class SettingsIO
{
  public static void WriteSettings(AppSettings settings, string settingsFilePath)
  {
    XmlSerializer serializer = new XmlSerializer(typeof(AppSettings));

    if (!Directory.Exists(Path.GetDirectoryName(settingsFilePath)))
      Directory.CreateDirectory(Path.GetDirectoryName(settingsFilePath));

    using (StreamWriter SW = new StreamWriter(settingsFilePath))
      serializer.Serialize(SW, settings);
  }

  public static AppSettings GetSettings(string settingsFilePath)
  {
    AppSettings m_Settings = null;

    if (File.Exists(settingsFilePath))
    {
      XmlSerializer serializer = new XmlSerializer(typeof(AppSettings));

      using (FileStream FS = new FileStream(settingsFilePath, FileMode.Open, FileAccess.Read, FileShare.ReadWrite))
        using (StreamReader SR = new StreamReader(FS))
          m_Settings = (AppSettings)serializer.Deserialize(SR);
    }

    if (m_Settings == null)
      m_Settings = new AppSettings();

    return m_Settings;
  }
}

在这里：

console.log(response.result);

之后使用适用的正确对象。

您可能想要使用

function makeApiCall() {
    gapi.client.people.people.get({
      'resourceName': 'people/me',
      'requestMask.includeField': 'person.names,person.emailAddresses'
    }).then(function(resp) {

      console.log(response.result);
      var name = resp.result.names[0].givenName;
      //var email = resp.result.emailAddresses[0].emailAddress;
      //authorizeButton.insertAdjacentHTML('beforebegin', '<small rel="' + email + '">Logged in as ' + name + '</small>');
    });
  }

使用Google People API登录用户的电子邮件

1 个答案: