当我更改select选项并将其保存到mysql而不重新加载页面时,我需要提交整个表单。
我有这个代码,但只有POST选择选项值,我也需要在表单中POST隐藏值。
<form class="form-horizontal" method="POST" action='#' name="dateForm">
<input type='hidden' name='cond_acao' class='form-control' value="edit_seccao_formando">
<input type="hidden" name="id_formando" value="<?=$linha_formandos[id_formando];?>">
<select name="id_seccoes" class="form-control" onchange="return postSelection">
<option selected="selected" value="1">car</option>
<option value="2">boat</option>
<option value="3">plane</option>
</select>
<div id='response_seccoes'></div>
<script>
function postSelection(selectObject) {
var id_seccoes = window.dateForm.id_seccoes.value = selectObject.options[selectObject.selectedIndex].value;
var dataString = "id_seccoes=" + id_seccoes;
$.ajax({
type: "post",
url: "url.php",
data: dataString,
success: function(response) {
$('#response_seccoes').html("ok").fadeIn(100).delay(2000).fadeOut("slow");
//$("#list").html(response);
}
});
return false;
};
</script>
</form>
可以序列化而不是指定字符串吗?
有人能帮帮我吗?谢谢
答案 0 :(得分:0)
您正在使用Jquery,我建议您使用jquery函数监视选择按钮以进行更改,例如
$("id_seccoes").change(function(){
//call your post method here.
});
答案 1 :(得分:0)
用此替换您的代码。
<form class="form-horizontal" method="POST" action='#' name="dateForm">
<input type='hidden' name='cond_acao' class='form-control' value="edit_seccao_formando">
<input type="hidden" name="id_formando" value="<?=$linha_formandos[id_formando];?>">
<select name="id_seccoes" class="form-control">
<option value="1">car</option>
<option value="2">boat</option>
<option value="3">plane</option>
</select>
</form>
<div id='response_seccoes'></div>
<script>
$(document).ready(function(){
$('[name="id_seccoes"]').change(function(){
$.post('url.php',$('[name="dateForm"]').serialize(),function(response){
$('#response_seccoes').html("ok").fadeIn(100).delay(2000).fadeOut("slow");
});
});
});
</script>