我想要做的是从url
下面获取json数据https://query.yahooapis.com/v1/public/yql?q=select * from
weather.forecast where woeid in (select woeid from geo.places(1) where
text='seoul,kr') and u='c'&format=json
如果在浏览器上键入它,效果很好。
但它在alamofire上工作...... 我认为这是因为'标记 我可以看到\是嵌入式说FATAL无效网址
let rrrr="https://query.yahooapis.com/v1/public/yql?q=select * from weather.forecast where woeid in (select woeid from geo.places(1) where text='seoul,kr') and u='c'&format=json"
print(rrrr)
let alamo=Alamofire.request(rrrr,method:.get)
alamo.responseJSON {
response in
if response.data != nil {
print("not null")
let json = JSON(data: response.data!)
print(json)
print("not null21")
print(response)
print("not null12")
print(response.data!)
日志结果如下
https://query.yahooapis.com/v1/public/yql?q=select * from weather.forecast where woeid in (select woeid from geo.places(1) where text='seoul,kr') and u='c'&format=json
not null
null
not null21
FAILURE: invalidURL("https://query.yahooapis.com/v1/public/yql?q=select * from weather.forecast where woeid in (select woeid from geo.places(1) where text=\'seoul,kr\') and u=\'c\'&format=json")
not null12
答案 0 :(得分:1)
正如我所见,您的URL字符串包含select query中的空格。
实际上,alamofire不支持带空格的URL字符串。尝试用%20
替换URL字符串空格(即编码字符空间)。
或者您可以将URL编码与Alamofire请求一起使用。
希望它会有所帮助!
答案 1 :(得分:0)
我用这个:
enum ConsultOfficesServiceEndpoints : String {
case getProposedPeople = "aaa/bbb/ccc/%d/"
}
.
.
.
func getProposedPeople(_ name: String, success: @escaping SuccessResponse,failure: @escaping FailureResponse){
var paramWithSpaces = ""
var lines = name.components(separatedBy: " ")
var numlines = lines.count
var i = 0
if numlines > 1{
while i < (numlines - 1) {
paramWithSpaces = paramWithSpaces + lines[i] + "%20"
i = i+1
}
paramWithSpaces = paramWithSpaces + lines[numlines - 1]
}else{
paramWithSpaces = name
}
self.GET(withEndpoint: ConsultOfficesServiceEndpoints.getProposedPeople.rawValue.replacingOccurrences(of: "%d", with: paramWithSpaces), params: nil, headers: nil, success: success, failure: failure)
}