我试图用PHP做一个简单的查询,它返回一个包含用户所有名字的字符串列表,但我可以弄明白该怎么做。我唯一想到的就是这个:
//You can easy cast it to your type or Convert it.
var _strValue = Sessions["page"].ToString() //if its string
但这会返回一个JSon,蚂蚁想法如何做到这一点?
答案 0 :(得分:2)
<?php
$host_name = "hostname";
$database = "database";
$user_name = "username";
$password = "pass";
$connect = mysqli_connect($host_name, $user_name, $password, $database);
$select = "SELECT username from userstasker";
$result = $connect->query($select);
$usernames = array();
while($r = mysqli_fetch_assoc($result)) {
$usernames[] = $r["username"];
}
$connect->close();
// Do something with $usernames
?>