我有两个数组,它们都包含随机键和值。我有一个更新的对象和当前对象。但更新的对象包含新值和旧值。我想找到这两个对象键和值之间的差异,以使用新的键或值生成新的更新对象。
当前对象
{
key1: "abc"
key2: "ggg"
key3: 0,
key4: ["1","3","5"]
key5: [1,2,3,4,5]
key6: [9,8,7,6],
key7: false
}
更新对象
{
key1: "abc"
key2: "new"
key3: 30,
key4: ["1","3","5"]
key5: [2,3,4]
key6: [],
key7: true,
special8: [1,2,3]
}
结果
{
key2: "new"
key3: 30,
key5: [2,3,4]
key6: [],
key7: true,
special8: [1,2,3]
}
答案 0 :(得分:2)
根据您的条件:以下reduce()
函数将每个updated
对象的属性与每个current
对象的属性进行比较,并返回包含差异的全新对象。
请注意:使用key4
简单地比较字符串数组(例如!==
属性)可以返回错误否定,因此使用JSON.stringify()
。
// Current Object.
const current = {
key1: "abc",
key2: "ggg",
key3: 0,
key4: ["1","3","5"],
key5: [1,2,3,4,5],
key6: [9,8,7,6],
key7: false
}
// Updated Object.
const updated = {
key1: "abc",
key2: "new",
key3: 30,
key4: ["1","3","5"],
key5: [2,3,4],
key6: [],
key7: true,
special8: [1,2,3]
}
// Difference Object.
const difference = (Object.keys(updated)).reduce((difference, key) => {
// Same?
if (JSON.stringify(updated[key]) == JSON.stringify(current[key])) return difference
// Different.
return {...difference, [key]: updated[key]}
}, {})
console.log(difference)
答案 1 :(得分:0)
以下内容将解决您的需求:
<article>
<section>content</section>
<section>content</section>
<section>cell3</section>
<section>cell4</section>
</article>
答案 2 :(得分:0)
这是另一种解决方案:
我们将使用两种不同的功能。等于函数的目的是查看相等的特定对象是否等于:
function equals(obj1, obj2) {
let equals = true;
if (!obj1) return;
if (obj1.length == obj2.length) {
for (var index in obj1) {
if (obj1[index] != obj2[index]) {
return false;
}
}
} else return false;
return true;
}
然后,实际的printDifferences函数利用上述函数来检查两个对象的差异。然后以另一个对象的形式返回。
function printDifferences(object1, object2) {
let newObj = {};
for (var key in object2) {
if ((typeof object1[key] == "object" && !equals(object1[key], object2[key])) ||
(typeof object1[key] != "object" && object1[key] != object2[key]) ||
object1[key] == undefined) {
newObj[key] = object2[key];
}
}
return newObj;
}
console.log(printDifferences(current, updated))