Question

我这里有问题，我的java代码是

int num = Integer.parseInt(mark.getText().toString());

我的xml代码是

android. InputType="number"

但我仍然收到错误说"invalid int =""" 任何人都可以帮助我..我现在真的需要帮助。

public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_adding_remove);
        parentLinearLayout = (LinearLayout) findViewById(R.id.parent_linear_layout);

        final EditText mark = (EditText)findViewById(R.id.etMark);
        EditText j = (EditText)findViewById(R.id.etJam);
        TextView status = (TextView)findViewById(R.id.tVGred);
        TextView pn = (TextView)findViewById(R.id.tvPnm);



        double  pointer;
        String grade;

       int num = Integer.parseInt(mark.getText().toString());

        if (num >= 90 && num <= 100) {
            grade = "A+";
            pointer = 4.00;
            status.setText(grade);
        }
        else if (num >= 80 && num <= 89) {
            grade = "A";
            pointer = 4.00;
            status.setText(grade);
        }
        else if (num >= 75 && num <= 79) {
            grade = "A-";
            pointer = 3.67;
            status.setText(grade);
        }
        else if (num >= 70 && num <= 74) {
            grade = "B+";
            pointer = 3.33;
            status.setText(grade);

        }
         else if (num >= 65 && num <= 69) {
            grade = "B";
            pointer = 3.00;
            status.setText(grade);
        }
        else if (num >= 60 && num <= 64) {
            grade = "B-";
            pointer = 2.67;
            status.setText(grade);
        }
        else if (num >= 55 && num <= 59) {
            grade = "C+";
            pointer = 2.33;
            status.setText(grade);
        }
        else if (num >= 50 && num <= 54) {
            grade = "C";
            pointer = 2.00;
            status.setText(grade);
        }
        else if (num >= 47 && num <= 49) {
            grade = "C-";
            pointer = 1.67;
            status.setText(grade);
        }
        else if (num >= 44 && num <= 46) {
            grade = "D+";
            pointer = 1.33;
            status.setText(grade);
        }
        else if (num >= 40 && num <= 43) {
            grade = "D";
            pointer = 1.00;
            status.setText(grade);
        }
        else
        {
            grade = "F";
            pointer = 0.00;
            status.setText(grade);
        }


   }

Answer 1

问题在于

 int num = Integer.parseInt(mark.getText().toString());

您的代码是尝试从EDITTEXT获取文本但是包含＆＃34;＆＃34;当ActiVity创建时。所以invalid Int的Activity Throw错误因此你需要添加任何Button So Activity Get String当Button按下Trigger时。但是，如果您不想使用任何按钮使用Enter键作为触发器来更改焦点并获得String Fri EditText，就像这样。

import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.KeyEvent;
import android.view.View;
import android.widget.EditText;
import android.widget.LinearLayout;
import android.widget.RelativeLayout;
import android.widget.ScrollView;
import android.widget.TextView;

public class Main2Activity extends AppCompatActivity {
    int num =0;
    EditText mark;
    EditText j;
    TextView status,pn;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main2);


        mark = (EditText)findViewById(R.id.edt);
         j = (EditText)findViewById(R.id.jmark);
         status = (TextView)findViewById(R.id.txt);
         pn = (TextView)findViewById(R.id.txt1);


        final double[] pointer = new double[1];
        final String[] grade = new String[1];





        mark.setOnKeyListener(new View.OnKeyListener() {
            public boolean onKey(View v, int keyCode, KeyEvent event) {
                if(KeyEvent.KEYCODE_ENTER == keyCode) {
                    j.requestFocus();
                    if(mark.getText().toString()!="")
                    num= Integer.parseInt(mark.getText().toString());
                    if (num >= 90 && num <= 100) {
                        grade[0] = "A+";
                        pointer[0] = 4.00;
                        status.setText(grade[0]);
                    }
                    else if (num >= 80 && num <= 89) {
                        grade[0] = "A";
                        pointer[0] = 4.00;
                        status.setText(grade[0]);
                    }
                    else if (num >= 75 && num <= 79) {
                        grade[0] = "A-";
                        pointer[0] = 3.67;
                        status.setText(grade[0]);
                    }
                    else if (num >= 70 && num <= 74) {
                        grade[0] = "B+";
                        pointer[0] = 3.33;
                        status.setText(grade[0]);

                    }
                    else if (num >= 65 && num <= 69) {
                        grade[0] = "B";
                        pointer[0] = 3.00;
                        status.setText(grade[0]);
                    }
                    else if (num >= 60 && num <= 64) {
                        grade[0] = "B-";
                        pointer[0] = 2.67;
                        status.setText(grade[0]);
                    }
                    else if (num >= 55 && num <= 59) {
                        grade[0] = "C+";
                        pointer[0] = 2.33;
                        status.setText(grade[0]);
                    }
                    else if (num >= 50 && num <= 54) {
                        grade[0] = "C";
                        pointer[0] = 2.00;
                        status.setText(grade[0]);
                    }
                    else if (num >= 47 && num <= 49) {
                        grade[0] = "C-";
                        pointer[0] = 1.67;
                        status.setText(grade[0]);
                    }
                    else if (num >= 44 && num <= 46) {
                        grade[0] = "D+";
                        pointer[0] = 1.33;
                        status.setText(grade[0]);
                    }
                    else if (num >= 40 && num <= 43) {
                        grade[0] = "D";
                        pointer[0] = 1.00;
                        status.setText(grade[0]);
                    }
                    else
                    {
                        grade[0] = "F";
                        pointer[0] = 0.00;
                        status.setText(grade[0]);
                    }

                    return true;
                }
                else
                {
                    return false;
                }

            }
        });
    }
}

确定你添加了android:singleLine="true"你的xml文件

Answer 2

use this    
<EditText
                android:id="@+id/login_text_phone"
                android:layout_width="match_parent"
                android:layout_height="wrap_content"
                android:background="@android:color/transparent"
                android:digits="0123456789"
                android:maxLength="10" />

Answer 3

try this 
int num = toInteger(mark.getText().toString());


    public static Integer toInteger(Object value) {
        if (value instanceof Integer) {
            return (Integer) value;
        } else if (value instanceof Number) {
            return ((Number) value).intValue();
        } else if (value instanceof String) {
            try {
                return (int) Double.parseDouble((String) value);
            } catch (NumberFormatException ignored) {
            }
        }
        return null;
    }

如何从edittext android studio获取数字输入类型

3 个答案: