Question

我有一个包含以下信息的var：

[[code=666]],[[code=777]],

我想迭代这些并将"666"和"777"保存在{"666","777"}这样的数组中。我尝试了以下内容，但将其保存为{"6","6, "6", "7", "7", "7"}。

var t = this;
var regex = /\[\[code=.*?\]\]/gi;
var match = t;
match = t.data.u_pricing.match(regex);

var final_code = [];

if (match != null) {
  //itereate through the matches eg. [[code=666]] [[code=777]]
  for (var i = 0; i < match.length; i++) {
    var init_index = match[i].indexOf("=") + 1;
    var end_index = match[i].length - 2;
    for (init_index; init_index < end_index; init_index++) {
      final_code.push(match[i][init_index]);
    }
    console.log("FINAL CODE" + final_code);
  }
}

Answer 1

你一直在推文。你可以使用slice（）作为例子。

var t = this;
var regex = /\[\[code=.*?\]\]/gi;
var match = t;
match = t.data.u_pricing.match(regex);

var final_code = [];

if (match != null) {
    console.log(match)

  //itereate through the matches eg. [[code=666]] [[code=777]]
  for (var i = 0; i < match.length; i++) {
    var init_index = match[i].indexOf("=") + 1;
    var end_index = match[i].length - 2;
    final_code.push(match[i].slice(init_index, end_index))
  }
  console.log(final_code);
}

Answer 2

由于安德烈亚斯和巴恩斯基的回答对你不起作用，也许会这样做：

＆＃13;

var str = '[[code=666]],[[code=777]]'; // this.data.u_pricing
var regex = /\[\[code=(.*?)\]\]/gi;
var match;

var final_code = [];

while (match = regex.exec(str)) {
  final_code.push(match[1]);
}

console.log(final_code);

＆＃13;

Answer 3

var test = '[[code=666]],[[code=777]]';
var result = [];
test.split(']]').forEach(function(str) {
    if(str.indexOf('[[code=') != -1) {
        result.push(str.replace('[[code=', ''));
    }
});
console.log(result);

迭代通过什么将它保存到数组中？

3 个答案: