我有两个选择框,用于加载联系人和联系人组,如何一次显示一个div,通过选中或取消选中复选框来切换它们? 下面的代码显示一个处于关闭状态,并在检查时显示两个而不是隐藏第一个并显示第二个。
代码段
$(document).ready(function () {
var checkbox = $('#checker');
var dependent = $('#dependent-box');
var dependent2 = $('#dependent-box2');
if (checkbox.attr('checked') !== undefined){
dependent.show();
dependent2.hide();
} else {
dependent2.show();
dependent.hide();
}
checkbox.change(function(e){
dependent.toggle();
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<input type="checkbox" id="checker" data-toggle="toggle">
<div id="dependent-box">
<div class="form-group" >
<select class="contact-multiple form-control" multiple="multiple" name="to_sms[]" id="toggle1" style="width: 98%;">
<option value="Hi">
Hi
</option>
</select>
</div>
</div>
<div id="dependent-box2">
<div class="form-group" >
<select class="contact-multiple form-control" multiple="multiple" name="to_sms[]" id="toggle1" style="width: 98%;">
<option value="Hi">
Hello
</option>
</select>
</div>
</div>
答案 0 :(得分:0)
您没有切换更改功能中的第二个框。
checkbox.change(function(e){
dependent.toggle();
dependent2.toggle();
});
答案 1 :(得分:0)
检查是否选中了检查器:
$(document).ready(function () {
var checkbox = $('#checker');
var dependent = $('#dependent-box');
var dependent2 = $('#dependent-box2');
dependent2.hide();
checkbox.change(function(e){
if(this.checked){
dependent.hide();
dependent2.show();
}else
{
dependent.show();
dependent2.hide();
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<input type="checkbox" id="checker" data-toggle="toggle">
<div id="dependent-box">
<div class="form-group" >
<select class="contact-multiple form-control" multiple="multiple" name="to_sms[]" id="toggle1" style="width: 98%;">
<option value="Hi">
Hi
</option>
</select>
</div>
</div>
<div id="dependent-box2">
<div class="form-group" >
<select class="contact-multiple form-control" multiple="multiple" name="to_sms[]" id="toggle1" style="width: 98%;">
<option value="Hi">
Hello
</option>
</select>
</div>
</div>