我有一些编译C函数的代码,使用PyUFunc_FromFuncAndData创建一个numpy泛型函数。我已经写了一些cython来创建ufunc,但是如果可能的话我想用ctypes来做,因为我打算分发它,我想避免用户编译步骤。
问题是PyUFunc_FromFuncAndData返回一个指向PyObject的指针。是否可以将它用作python代码中的对象?
基本上,我希望能够将以下cython代码翻译成python / ctypes:
from numpy cimport NPY_DOUBLE
from libc.stdlib cimport malloc, free
cdef extern from "numpy/ufuncobject.h":
ctypedef void (*PyUFuncGenericFunction) (char **, Py_ssize_t *, Py_ssize_t *, void *)
object PyUFunc_FromFuncAndData (PyUFuncGenericFunction *, void **, char *, int, int, int, int, char *, char *, int)
void import_ufunc()
import_ufunc()
cdef class UFuncWrapper:
cdef readonly object func
cdef object _llvm_func
cdef PyUFuncGenericFunction function
cdef char *types
cdef bytes name
def __init__(self, func, ufunc, long long ptr):
self._llvm_func = ufunc # keep a ref to prevent it from being gced
cdef int num_args = len(func.args)
self.types = <char*>malloc(sizeof(char)*(num_args+1))
self.name = func.name
cdef int i
for i in range(num_args+1):
self.types[i] = NPY_DOUBLE
self.function = <PyUFuncGenericFunction>ptr
self.func = PyUFunc_FromFuncAndData(
&self.function,
NULL,
self.types,
1, #ntypes
num_args,
1,
-1, # PyUFunc_None,
self.name,
self.name, #FIXME: __doc__
0)
def __dealloc__(self):
free(self.types)
def __call__(self, *args):
return self.func(*args)
答案 0 :(得分:3)
将该函数的重新类型设置为ctypes.py_object。下面的示例使用对python C-API的调用,但它对其他任何内容都是一样的。
import ctypes
class Foo(object):
bar='baz'
foo=ctypes.py_object(Foo)
print 'Memory adress of Foo.bar object:',
print ctypes.pythonapi.PyObject_GetAttrString(foo,'bar') # prints the pointer
ctypes.pythonapi.PyObject_GetAttrString.restype = ctypes.py_object
print 'Actual Foo.bar after we set restype correctly:',
print ctypes.pythonapi.PyObject_GetAttrString(foo,'bar') # prints "baz"