建立对自定义python的提升

时间:2017-11-07 16:40:24

标签: python c++ boost-python

我正在尝试针对我的自定义构建的python编译boost并获取" undefined reference"错误。详细信息如下:

1)我根据autodesk maya的要求构建了支持unicode = ucs4的python

./configure --prefix=/v/pkgs/python/dep/2.7.14 --enable-unicode=ucs4
make
make install

2)使用此命令构建提升

b2 -j 4 --layout=versioned --build-type=complete --debug-configuration stage

和配置文件./tools/build/src/user-config.jam使用我的python构建。

using python
    : 2.7
    : /v/pkgs/python/dep/2.7.14
    ;

这是b2输出的一部分,用于确认python选择成功:

notice: [python-cfg] Configuring python...
notice: [python-cfg]   user-specified version: "2.7"
notice: [python-cfg]   user-specified cmd-or-prefix: "/v/pkgs/python/dep/2.7.14"
notice: [python-cfg] Checking interpreter command "/v/pkgs/python/dep/2.7.14/bin/python2.7"...
notice: [python-cfg] running command '/v/pkgs/python/dep/2.7.14/bin/python2.7 -c "from sys import *; print('version=%d.%d\nplatform=%s\nprefix=%s\nexec_prefix=%s\nexecutable=%s' % (version_info[0],version_info[1],platform,prefix,exec_prefix,executable))" 2>&1'
notice: [python-cfg] ...requested configuration matched!
notice: [python-cfg] Details of this Python configuration:
notice: [python-cfg]   interpreter command: "/v/pkgs/python/dep/2.7.14/bin/python2.7"
notice: [python-cfg]   include path: "/v/pkgs/python/dep/2.7.14/include/python2.7"
notice: [python-cfg]   library path: "/v/pkgs/python/dep/2.7.14/lib/python2.7/config" "/v/pkgs/python/dep/2.7.14/lib"

3)验证我尝试构建以下test.cpp

#include <Python.h>
#include <boost/python.hpp>
int main ()
{
    Py_Initialize();
    boost::python::object obj;
    return 0;
}

使用此命令(更易于阅读的新行):

g++ -g -O2 
-I/v/pkgs/python/dep/2.7.14/include/python2.7 
-I/v/pkgs/boost/dep/1_61_0 
-L/v/pkgs/boost/dep/1_61_0/stage/lib 
-lboost_python-gcc48-mt-1_61
-L/v/pkgs/python/dep/2.7.14/lib 
-lpython2.7 
./test.cpp

我收到以下错误:

/v/pkgs/boost/dep/1_61_0/stage/lib/libboost_python-gcc48-mt-1_61.so: undefined reference to `PyUnicodeUCS4_FromEncodedObject'
/v/pkgs/boost/dep/1_61_0/stage/lib/libboost_python-gcc48-mt-1_61.so: undefined reference to `PyUnicodeUCS4_AsWideChar'

欢迎任何提示,谢谢!

1 个答案:

答案 0 :(得分:0)

似乎python不是使用UCS-4构建的,而是使用UCS-2构建的。 为了对此进行检查,请参考与this answer类似的问题。