Question

#include <stdio.h>
#include <string.h>
#define NAME_LEN 25

void listNames(int PEOPLE, char Lname[][NAME_LEN]);
void printNames(int PEOPLE, char Lname[][NAME_LEN]);
void getName(char name[]);

int main(void)
{
    int PEOPLE = 10;
    int member = 0;
    char name[NAME_LEN];
    char Lname[PEOPLE][NAME_LEN];
    listNames(PEOPLE, Lname);
    printNames(PEOPLE, Lname);
    return 0;
}

void listNames(int PEOPLE, char Lname[][NAME_LEN])
{
    int i;
    for (i = 0; i < PEOPLE; i++)
    {
        printf("Enter name: ");
        scanf("%[^\n]", Lname[i]);
        getchar();
    }
}

//Displays the names//
void printNames(int PEOPLE, char Lname[][NAME_LEN])
{
    int i;
    printf("\nList of names:\n");
    for (i = 0; i < PEOPLE; i++)
    {
        printf("Names: %-15s\n", Lname[i]);
    }
}

我不知道如何更改显示后输入的名称。

Answer 1

你的意思是基于索引的变化。

int idx = 0 ;
for( ; idx < PEOPLE; idx ++ ) {
  sprintf( Lname[idx], "%s", "New LName");
}

或根据名称本身进行更改？

int idx = 0 ;
for( ; idx < PEOPLE; idx ++ ) {
  if( strcmp( Lname[idx], "OriginalName") == 0 ) {
       sprintf( Lname[idx], "%s", "New LName");
       break;
  }
}

如何更改显示后输入的名称

1 个答案: