Question

我有一个带有此签名的方法：

x = 5

我想确认在y = 10和{ "name": "test2Fullcalendar", "private": true, "version": "0.0.0", "scripts": { "test": "karma start ClientApp/test/karma.conf.js" }, "dependencies": { "@angular/animations": "4.2.5", "@angular/common": "4.2.5", "@angular/compiler": "4.2.5", "@angular/compiler-cli": "4.2.5", "@angular/core": "4.2.5", "@angular/forms": "4.2.5", "@angular/http": "4.2.5", "@angular/platform-browser": "4.2.5", "@angular/platform-browser-dynamic": "4.2.5", "@angular/platform-server": "4.2.5", "@angular/router": "4.2.5", "@ngtools/webpack": "1.5.0", "@types/fullcalendar": "^3.5.1", "@types/jquery": "^3.2.16", "@types/webpack-env": "1.13.0", "angular2-template-loader": "0.6.2", "aspnet-prerendering": "^3.0.1", "aspnet-webpack": "^2.0.1", "awesome-typescript-loader": "3.2.1", "bootstrap": "3.3.7", "css": "2.2.1", "css-loader": "0.28.4", "es6-shim": "0.35.3", "event-source-polyfill": "0.0.9", "expose-loader": "0.7.3", "extract-text-webpack-plugin": "2.1.2", "file-loader": "0.11.2", "fullcalendar": "^3.6.2", "html-loader": "0.4.5", "isomorphic-fetch": "2.2.1", "jquery": "3.2.1", "json-loader": "0.5.4", "moment": "^2.19.1", "preboot": "4.5.2", "raw-loader": "0.5.1", "reflect-metadata": "0.1.10", "rxjs": "5.4.2", "style-loader": "0.18.2", "to-string-loader": "1.1.5", "typescript": "2.4.1", "url-loader": "0.5.9", "webpack": "2.5.1", "webpack-hot-middleware": "2.18.2", "webpack-merge": "4.1.0", "zone.js": "0.8.12" }, "devDependencies": { "@types/chai": "4.0.1", "@types/jasmine": "2.5.53", "chai": "4.0.2", "jasmine-core": "2.6.4", "karma": "1.7.0", "karma-chai": "0.1.0", "karma-chrome-launcher": "2.2.0", "karma-cli": "1.0.1", "karma-jasmine": "1.1.0", "karma-webpack": "2.0.3" } }时，此方法被正确调用了2次。我怎么能用Typemock做到这一点？

Answer 1

我放了一下，想出了以下内容：

鉴于课程：

public class Bar
{
    public static void Foo(int x, int y)
    {
        //do something...
        Debug.WriteLine($"Method called with {x} {y}");
    }
}

您的测试将如下所示：

[TestClass]
public class Test
{
    [TestMethod]
    public void TestMethod()
    {
        var callCount = 0;

        Isolate.WhenCalled(() => Bar.Foo(2, 10))
            .WithExactArguments()
            .DoInstead(context =>
            {
                callCount++;
                context.WillCallOriginal();
            });

        Bar.Foo(2, 6);
        Bar.Foo(2, 10);
        Bar.Foo(2, 10);

        Assert.AreEqual(2, callCount);
    }
}

断言使用Typemock使用精确参数调用方法x次

1 个答案: