插入多个拆分的字符串列以将行分隔为sql表

时间:2017-11-07 04:01:09

标签: sql sql-server sql-server-2008 sql-server-2008-r2

我有一张如下所示的表格

enter image description here

是否可以将上表数据插入到单独行中的表中?

enter image description here

我尝试在每列上使用split函数并将每个列结果存储在临时表中。我不知道如何根据id将所有这些行和列组合到新表中。任何帮助或建议都会有所帮助。

5 个答案:

答案 0 :(得分:1)

试试这个答案。希望这会对你有所帮助。

DECLARE @Table TABLE(ID INT, NAME VARCHAR(10),TITLE VARCHAR(10))
INSERT INTO @Table VALUES (1,';a;b;c',';12;13;14')

DECLARE @ID INT=1

SELECT @ID ID,Items,ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) RN1 INTO #T1 FROM dbo.split((SELECT NAME FROM @Table WHERE id=@ID),';')
SELECT @ID ID,Items,ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) RN2 INTO #T2 FROM dbo.split((SELECT TITLE FROM @Table WHERE id=@ID),';')

SELECT T1.ID,T1.Items NAME,T2.Items TITLE
FROM #T1 T1 INNER JOIN #T2 T2 ON T1.RN1=T2.RN2 

DROP TABLE #T1
DROP TABLE #T2

如果您想要所有值,只需尝试像WHILE这样的循环方法。

DECLARE @Table TABLE(ID INT, NAME VARCHAR(10),TITLE VARCHAR(10))
INSERT INTO @Table VALUES (1,';a;b;c',';12;13;14'),(2,';c;f;u',';67;56;34'),(3,';l;k;m',';90;70;60')

DECLARE @MinID INT,@MaxID INT
SELECT @MinID=MIN(ID),@MaxID=MAX(ID) FROM @Table

CREATE TABLE #T1(ID INT,Items VARCHAR(10),RN1 INT)
CREATE TABLE #T2(ID INT,Items VARCHAR(10),RN2 INT)

WHILE @MinID<=@MaxID
BEGIN
    INSERT  INTO #T1
    SELECT @MinID ID,Items,ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) RN1 
    FROM dbo.split((SELECT NAME FROM @Table WHERE id=@MinID),';')

    INSERT  INTO #T2
    SELECT @MinID ID,Items,ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) RN2 
    FROM dbo.split((SELECT TITLE FROM @Table WHERE id=@MinID),';')

    SET @MinID=@MinID+1
END

    SELECT T1.ID,T1.Items NAME,T2.Items TITLE
    FROM #T1 T1 INNER JOIN #T2 T2 ON T1.ID=T2.ID AND T1.RN1=T2.RN2 

DROP TABLE #T1
DROP TABLE #T2

这将产生结果,你真正想要的是什么:

ID          NAME       TITLE
----------- ---------- ----------
1           a          12
1           b          13
1           c          14
2           c          67
2           f          56
2           u          34
3           l          90
3           k          70
3           m          60

这是split函数,我以前用来分割字符串:

CREATE FUNCTION [dbo].[Split]
(@String VARCHAR (max), @Delimiter CHAR (1))
RETURNS 
    @temptable TABLE (
        [items] VARCHAR (max) COLLATE SQL_Latin1_General_CP1_CI_AS NULL)
AS
begin        
    declare @idx int        
    declare @slice varchar(max)        

    select @idx = 1        
        if len(@String)<1 or @String is null  return        

    while @idx!= 0        
    begin        
        set @idx = charindex(@Delimiter,@String)        
        if @idx!=0        
            set @slice = left(@String,@idx - 1)        
        else        
            set @slice = @String        

        if(len(@slice)>0)   
            insert into @temptable(Items) values(@slice)        

        set @String = right(@String,len(@String) - @idx)        
        if len(@String) = 0 break        
    end    
return        
end

答案 1 :(得分:1)

以下是CTE节点XML的另一种方法

无需创建任何功能。

WITH cte AS (
     SELECT ID,
            split.a.value('.', 'NVARCHAR(MAX)') [name],
            ROW_NUMBER() OVER(ORDER BY ( SELECT 1)) RN
     FROM
     (
         SELECT ID,
                CAST('<A>'+REPLACE(name, ';', '</A><A>')+'</A>' AS XML) AS [name]
         FROM <table_name>
     ) a
     CROSS APPLY name.nodes('/A') AS split(a)),
     CTE1 AS (
     SELECT ID,
            split.a.value('.', 'NVARCHAR(MAX)') [title],
            ROW_NUMBER() OVER(ORDER BY ( SELECT 1 )) RN
     FROM
     (
         SELECT ID,
                CAST('<A>'+REPLACE(title, ';', '</A><A>')+'</A>' AS XML) AS [title]
         FROM <table_name>
     ) aa
     CROSS APPLY title.nodes('/A') AS split(a))
     SELECT C.ID, C.name, C1.title FROM CTE C
          JOIN CTE1 C1 ON C1.RN = C.RN
     WHERE C.name != '' AND C1.title != '';

结果:

ID  name title
1   a    12
1   b    13
1   s    45
2   c    67
2   f    56
2   u    34
3   l    90
3   k    70
3   m    60

答案 2 :(得分:0)

尝试以下方式..这也将节省时间和内存!

  

此T-SQL块依赖于 dbo.SplitString 功能。
  T1是我的源表
T2是我的目标表

DECLARE @c_s AS CURSOR;
DECLARE @id INT;
DECLARE @name VARCHAR(1000);
DECLARE @value VARCHAR(1000);

SET @c_s = CURSOR FOR SELECT * FROM T1; 
OPEN @c_s;
FETCH @c_s INTO @id, @name, @value

WHILE @@FETCH_STATUS = 0
BEGIN
    INSERT INTO T2
    SELECT @id
        , a.Value NAME
        , b.value value
    FROM dbo.SplitString(@name, ';') a
    INNER JOIN dbo.SplitString(@value, ';') b
        ON a.OrdinalPosition = b.OrdinalPosition

  FETCH NEXT FROM @c_s INTO @id, @name, @value
END
  

这里是 dbo.SplitString

CREATE FUNCTION [dbo].[SplitString](@givenString VARCHAR(8000) , @separator VARCHAR(100))
RETURNS TABLE AS
RETURN (
        WITH data([start], [end]) AS (
                SELECT 0 AS [start]
                    , CHARINDEX(@separator, @givenString) AS [end]
                UNION ALL
                SELECT [end] + 1
                    , CHARINDEX(@separator, @givenString, [end] + 1)
                FROM data
                WHERE [end] > 0
                )
        SELECT ROW_NUMBER() OVER (
                ORDER BY OrdinalPosition
                ) OrdinalPosition
            , RTRIM(LTRIM(Value)) Value
        FROM (
            SELECT ROW_NUMBER() OVER (
                    ORDER BY [start]
                    ) OrdinalPosition
                , SUBSTRING(@givenString, [start], COALESCE(NULLIF([end], 0), len(@givenString) + 1) - [start]) Value
            FROM data
            ) r
        WHERE RTRIM(Value) <> ''
            AND Value IS NOT NULL
        )

答案 3 :(得分:0)

您可以通过编写一个表值函数来实现这一点,该函数将根据您的要求拆分字符串。创建此对象后,您可以在第二个代码段中使用T-SQL来获取最终所需的表。

此表值函数的定义如下所示。只需将其复制并粘贴到SSMS中,然后针对您的数据库运行它。

拆分字符串函数

-- =============================================
-- Author:      B Vidhya
-- Create date: Nov 7, 2017
-- Description: Splits a string and returns a table
-- =============================================
CREATE FUNCTION [dbo].[SplitAString]
(    
      @string NVARCHAR(MAX),
      @delimiter CHAR(1)
)
RETURNS @splitTable TABLE (
      ItemNumber INT IDENTITY(1,1),
      Item NVARCHAR(1000)
)
AS
BEGIN
      DECLARE @startIndex INT,@endIndex INT

      SET @startIndex = 1
      IF SUBSTRING(@string, LEN(@string) - 1, LEN(@string)) <> @delimiter
      BEGIN
            SET @string = @string + @delimiter
      END

      WHILE CHARINDEX(@delimiter, @string) > 0
      BEGIN
            SET @endIndex = CHARINDEX(@delimiter, @string)

            INSERT INTO @splitTable(Item)
            SELECT SUBSTRING(@string, @startIndex, @endIndex - 1)

            SET @string = SUBSTRING(@string, @endIndex + 1, LEN(@string))
      END

      RETURN
END

GO

在下面的T-SQL中,我调用了原始表StackOverflowTable1,您可以将此表名替换为您的实际表名。另外,我将最后一行插入表变量中。如果要插入自定义表,那么可以在WHILE循环结束后使用INSERT进入表。

T-SQL获得决赛桌

DECLARE @myTable TABLE
(Id    INT,
 Name  VARCHAR(5000),
 Title VARCHAR(5000)
);

DECLARE @lastId INT= 0, @id INT, @name VARCHAR(5000), @title VARCHAR(5000);

--for each record in table perform splitting and insertion in new table
WHILE EXISTS
(
    SELECT 1
    FROM StackOverFlowTable1 soft
    WHERE Id > @lastId
)
    BEGIN
        SELECT TOP (1) @id = Id,
                       @name = Name,
                       @title = Title
        FROM StackOverFlowTable1 soft
        WHERE Id > @lastId
        ORDER BY Id;
        SET @lastId = @id;
        INSERT INTO @myTable
        (Id,
         Name,
         Title
        )
               SELECT @id,
                      ss1.Item,
                      ss2.Item
               FROM dbo.SplitString(@name, ';') ss1
                    INNER JOIN dbo.SplitString(@title, ';') ss2 ON ss1.ItemNumber = ss2.ItemNumber
               WHERE ss1.Item <> ''
                     AND ss2.Item <> '';
    END;

SELECT * FROM @myTable;

答案 4 :(得分:0)

我不同意Dinesh脚本,因为它基于RBAR。

我有非常相似的分割功能,同时返回row_number和item。

所以测试我的脚本以及其他样本数据。

DECLARE @Table TABLE(ID INT, NAME VARCHAR(10),TITLE VARCHAR(10))
INSERT INTO @Table VALUES (1,',a,b,c',',12,13,14')

SELECT id
    ,t.RowVal
    ,a.RowVal
FROM (
    SELECT t.id
        ,a.RowNum
        ,a.RowVal
        ,t.TITLE
    FROM @Table t
    CROSS APPLY (
        SELECT *
        FROM dbo.FN_SPLIT_VALUE(t.NAME)
        ) a
    ) t
CROSS APPLY (
    SELECT *
    FROM dbo.FN_SPLIT_VALUE(t.TITLE)
    WHERE t.RowNum = RowNum
    ) a
WHERE t.RowVal <> ''