我有一系列不同的练习:
exercises: {
push: ['Push up', 'Bench press'],
legs: ['Squat', 'Power squats'],
pull: ['Pull up', 'Chin up'],
cardioCore: ['Running high knees', 'Plank']
}
如何将所有这些组合成一个数组或对象?我需要创建这个:
allExercises: ['Push up', 'Bench press', 'Squat', 'Power squats', 'Pull up', 'Chin up', 'Running high knees', 'Plank']
我也会按字母顺序排序,所以顺序并不重要。
我想我可以使用forEach
执行此操作,如下所示:
let allExercises = [];
exercises.forEach(exerciseGroup=>{
allExercises.push(exerciseGroup);
});
但这感觉有点乱。有更好的ES6解决方案吗?
答案 0 :(得分:2)
是的,只需使用Object.values
和Array.prototype.reduce
。
const allExercises = Object.values(exercises)
.reduce((array, subarray) => array.concat(subarray), []);
答案 1 :(得分:2)
这是另一种方式,ES6兼容。:
Object.getOwnPropertyNames(exercises)
.reduce((allExercises, exerciseName) => [...allExercises, ...(exercises[exerciseName])], [])
正如@stealththeninja所说,你也可以这样做以减少一大堆开销。
Object.getOwnPropertyNames(exercises).reduce((allExercises, exerciseName) => {
allExercises.push(...exercises[exerciseName]);
return allExercises;
}, []);
答案 2 :(得分:0)
[].concat.apply([], Object.values(exercises));
答案 3 :(得分:0)
我丑陋的解决方案:
let combineExercises = [];
Object.values(allExercises).forEach((exerciseGroup) => {
exerciseGroup.forEach((exercise) => {
combineExercises.push(exercise)
})
});
console.log(combineExercises);
答案 4 :(得分:0)
您可以使用Object.values
& spread operator
var exercises = {
push: ['Push up', 'Bench press'],
legs: ['Squat', 'Power squats'],
pull: ['Pull up', 'Chin up'],
cardioCore: ['Running high knees', 'Plank']
}
var allexercise ={},tempArray=[];
for(var keys in exercises){
tempArray.push(...Object.values(exercises[keys]))
}
allexercise=tempArray;
console.log(allexercise)