Question

你好有办法在laravel或php中获得两个foreach的区别。这是我的示例代码

    @foreach($budgets as $budget)
         $budget->b_amount
    @endforeach

    @foreach($purchases as $purchase)
       $purchase->p_amount
    @endforeach

所以基本上我需要得到每个foreach的所有值，然后取各自的差异。有没有办法做到这一点？像这样......

 <?php 
  $diff =  $budget->b_amount - $purchase->p_amount;
 ?>

非常感谢你。

Answer 1

@if(count($budgets) == count($purchases))
@foreach($budgets as $key => $value)
     $diff[] = $budgets[$key]->b_amount - $purchases[$key]->p_amount
@endforeach
@endif

现在$diff包含一系列差异。

Answer 2

首先，如果你能确保数组中的所有对象都是数值，你可以使用下面的函数：

function diff($budgets, $purchases) {
    $b = 0;
    $p = 0;
    foreach ($budgets as $budget) {
        $b += $budget;
    }
    foreach ($purchases as $purchase) {
        $p += $purchase;
    }
    return $b-$p;
}

此外，如果你只需要忽略+/-符号：

function diff($budgets, $purchases) {
    $b = 0;
    $p = 0;
    foreach ($budgets as $budget) {
        $b += $budget;
    }
    foreach ($purchases as $purchase) {
        $p += $purchase;
    }
    return abs($b-$p);
}

但是，如果您不确定数值是否在数组中：

function diff($budgets, $purchases) {
    $b = 0;
    $p = 0;
    foreach ($budgets as $budget) {
        $b += is_numeric($budget)?$budget:0;
    }
    foreach ($purchases as $purchase) {
        $p += is_numeric($purchase)?$purchase:0;
    }
    return $b-$p;
}

如何在PHP Laravel中计算两个foreach的每个数组值

2 个答案: