Question

我正在使用org.apache.commons.codec.binary.Base64做解码字符串，这是utf8。有时我会得到base64编码的字符串，在解码后看起来像^@kďż˝ďż˝@@。如何检查base64是否正确或解码的utf8字符串是否有效？utf8 string？

澄清。我正在使用

public static String base64Decode(String str) {
    try {
        return new String(base64Decode(str.getBytes(Constants.UTF_8)), Constants.UTF_8);
    } catch (UnsupportedEncodingException e) {
         ...
    }
}

public static byte[] base64Decode(byte[] byteArray) {
    return Base64.decodeBase64(byteArray);
}

Answer 1

您应该在将String转换为byte[]时指定字符集，反之亦然。

byte[] bytes = string.getBytes("UTF-8");
// feed bytes to Base64

和

// get bytes from Base64
String string = new String(bytes, "UTF-8");

否则将使用平台默认编码，本身不一定是UTF-8。

Answer 2

试试这个：

var B64 = {
    alphabet: 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=',
    lookup: null,
    ie: /MSIE /.test(navigator.userAgent),
    ieo: /MSIE [67]/.test(navigator.userAgent),
    encode: function (s) {
        var buffer = B64.toUtf8(s),
            position = -1,
            len = buffer.length,
            nan1, nan2, enc = [, , , ];
        if (B64.ie) {
            var result = [];
            while (++position < len) {
                nan1 = buffer[position + 1], nan2 = buffer[position + 2];
                enc[0] = buffer[position] >> 2;
                enc[1] = ((buffer[position] & 3) << 4) | (buffer[++position] >> 4);
                if (isNaN(nan1)) enc[2] = enc[3] = 64;
                else {
                    enc[2] = ((buffer[position] & 15) << 2) | (buffer[++position] >> 6);
                    enc[3] = (isNaN(nan2)) ? 64 : buffer[position] & 63;
                }
                result.push(B64.alphabet[enc[0]], B64.alphabet[enc[1]], B64.alphabet[enc[2]], B64.alphabet[enc[3]]);
            }
            return result.join('');
        } else {
            result = '';
            while (++position < len) {
                nan1 = buffer[position + 1], nan2 = buffer[position + 2];
                enc[0] = buffer[position] >> 2;
                enc[1] = ((buffer[position] & 3) << 4) | (buffer[++position] >> 4);
                if (isNaN(nan1)) enc[2] = enc[3] = 64;
                else {
                    enc[2] = ((buffer[position] & 15) << 2) | (buffer[++position] >> 6);
                    enc[3] = (isNaN(nan2)) ? 64 : buffer[position] & 63;
                }
                result += B64.alphabet[enc[0]] + B64.alphabet[enc[1]] + B64.alphabet[enc[2]] + B64.alphabet[enc[3]];
            }
            return result;
        }
    },
    decode: function (s) {
        var buffer = B64.fromUtf8(s),
            position = 0,
            len = buffer.length;
        if (B64.ieo) {
            result = [];
            while (position < len) {
                if (buffer[position] < 128) result.push(String.fromCharCode(buffer[position++]));
                else if (buffer[position] > 191 && buffer[position] < 224) result.push(String.fromCharCode(((buffer[position++] & 31) << 6) | (buffer[position++] & 63)));
                else result.push(String.fromCharCode(((buffer[position++] & 15) << 12) | ((buffer[position++] & 63) << 6) | (buffer[position++] & 63)));
            }
            return result.join('');
        } else {
            result = '';
            while (position < len) {
                if (buffer[position] < 128) result += String.fromCharCode(buffer[position++]);
                else if (buffer[position] > 191 && buffer[position] < 224) result += String.fromCharCode(((buffer[position++] & 31) << 6) | (buffer[position++] & 63));
                else result += String.fromCharCode(((buffer[position++] & 15) << 12) | ((buffer[position++] & 63) << 6) | (buffer[position++] & 63));
            }
            return result;
        }
    },
    toUtf8: function (s) {
        var position = -1,
            len = s.length,
            chr, buffer = [];
        if (/^[\x00-\x7f]*$/.test(s)) while (++position < len)
        buffer.push(s.charCodeAt(position));
        else while (++position < len) {
            chr = s.charCodeAt(position);
            if (chr < 128) buffer.push(chr);
            else if (chr < 2048) buffer.push((chr >> 6) | 192, (chr & 63) | 128);
            else buffer.push((chr >> 12) | 224, ((chr >> 6) & 63) | 128, (chr & 63) | 128);
        }
        return buffer;
    },
    fromUtf8: function (s) {
        var position = -1,
            len, buffer = [],
            enc = [, , , ];
        if (!B64.lookup) {
            len = B64.alphabet.length;
            B64.lookup = {};
            while (++position < len)
            B64.lookup[B64.alphabet[position]] = position;
            position = -1;
        }
        len = s.length;
        while (position < len) {
            enc[0] = B64.lookup[s.charAt(++position)];
            enc[1] = B64.lookup[s.charAt(++position)];
            buffer.push((enc[0] << 2) | (enc[1] >> 4));
            enc[2] = B64.lookup[s.charAt(++position)];
            if (enc[2] == 64) break;
            buffer.push(((enc[1] & 15) << 4) | (enc[2] >> 2));
            enc[3] = B64.lookup[s.charAt(++position)];
            if (enc[3] == 64) break;
            buffer.push(((enc[2] & 3) << 6) | enc[3]);
        }
        return buffer;
    }
};

查看Here

Answer 3

我创建了这个方法：

public static String descodificarDeBase64(String stringCondificado){
    try {
        return new String(Base64.decode(stringCondificado.getBytes("UTF-8"),Base64.DEFAULT));
    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
        return "";
    }
}

所以我可以将Base64西班牙语字符解码为á，ñ，í，ü。

示例：

descodificarDeBase64("wr9xdcOpIHRhbD8=");

将返回：¿Quétal？

Java BASE64 utf8字符串解码

3 个答案: