Question

我需要使用带有insuredId的jolt框架删除json消息中的重复项，并将唯一的insuredId和insuredName分别复制到namecode和name，我已经实现了使用insuredId删除重复但我不知道如何复制相应的保险名称随之而来。

输入：

[
  {
    "aircraftId": "ILTA",
    "aircraftTypeCode": "",
    "insuredId": "12020671",
    "insuredName": "Samuel Antony",
    "policyReference": "20081238",
    "uwy": "2017"
  },
  {
    "aircraftId": "ILTA",
    "aircraftTypeCode": "",
    "insuredId": "12020671",
    "insuredName": "Samuel Antony",
    "policyReference": "20081238",
    "uwy": "2017"
  },
  {
    "aircraftId": "ADE",
    "aircraftTypeCode": "",
    "insuredId": "12018832",
    "insuredName": "Mark henry",
    "policyReference": "20082780",
    "uwy": "2017"
  }
]

Jolt Spec：

[
  {
    "operation": "shift",
    "spec": {
      "*": { 
        "insuredId": { 
          "*": "ids.&[]"
        }
      }
    }
  },
  {
    "operation": "shift",
    "spec": {
      "ids": {
        "*": {
          "$": "[#2].nameCode" 
        }
      }
    }
  }
]

实际输出：

[
  {
    "nameCode": "12020671"
  },
  {
    "nameCode": "12018832"
  }
]

预期产出：

[
  {
    "nameCode": "12020671",
    "name":"Samuel Antony"
  },
  {
    "nameCode": "12018832",
    "name":"Mark henry"
  }
]

更新的规范（需要验证）：

[
  {
    "operation": "shift",
    "spec": {
      "*": {
        "insuredId": {
          "*": "ids.&[]"
        },
        "insuredName": {
          "*": "insuredNames.&[]"
        }
      }
    }
  },
  {
    "operation": "shift",
    "spec": {
      "ids": {
        "*": {
          "$": "[#2].nameCode"
        }
      },
      "insuredNames": {
        "*": {
          "$": "[#2].name"
        }
      }
    }
  }
]

Answer 1

[
  {
    "operation": "shift",
    "spec": {
      "*": {
        "insuredId": {
          "*": {
            "@(2,insuredName)": "ids.&[]"
          }
        }
      }
    }
  },
  {
    "operation": "shift",
    "spec": {
      "ids": {
        "*": {
          "$": "[#2].nameCode",
          "*": "[#2].name"
        }
      }
    }
  },
  {
    "operation": "modify-overwrite-beta",
    "spec": {
      "*": {
        "name": "=firstElement(@(1,name))"
      }
    }
  }
]

解释

第一次操作：

[
  {
    "operation": "shift",
    "spec": {
      "*": {
        "insuredId": {
          "*": {
            "@(2,insuredName)": "ids.&[]"
          }
        }
      }
    }
  }
]

它收集有＆＃34; insuredId＆＃34;作为＆＃34; insuredName＆＃34;的关键和列表作为价值观：

{
  "ids" : {
    "12020671" : [ "Samuel Antony", "Samuel Antony" ],
    "12018832" : [ "Mark henry" ]
  }
}

第二次操作：

[
  {
    "operation": "shift",
    "spec": {
      "ids": {
        "*": {
          "$": "[#2].nameCode",
          "*": "[#2].name"
        }
      }
    }
  }
]

它将地图转换为简单的对列表：

[ {
  "nameCode" : "12018832",
  "name" : "Mark henry"
}, {
  "nameCode" : "12020671",
  "name" : [ "Samuel Antony", "Samuel Antony" ]
} ]

第三次操作：

[
  {
    "operation": "modify-overwrite-beta",
    "spec": {
      "*": {
        "name": "=firstElement(@(1,name))"
      }
    }
  }
]

它需要包含名称的数组的第一个元素：

[ {
  "nameCode" : "12018832",
  "name" : "Mark henry"
}, {
  "nameCode" : "12020671",
  "name" : "Samuel Antony"
} ]

Answer 2

您可以使用四个连续的shift变换。在第一步中单独选择每个所需的键，以便为每个键获得两个列表。在第二步中使每个列表中的元素都是唯一的。在这一步中，我们有两个带键的对象。然后再次将它们转换为列表。并根据每个列表中的索引将它们分组到没有键的对象中，例如

[
  {
    "operation": "shift",
    "spec": {
      "*": {
        "insuredId": "&",
        "insuredName": "&"
      }
    }
  },
  {
    "operation": "shift",
    "spec": {
      "*": {
        "*": {
          "*": "&2.&"
        }
      }
    }
  },
  {
    "operation": "shift",
    "spec": {
      "*": {
        "*": {
          "$": "&2"
        }
      }
    }
  },
  {
    "operation": "shift",
    "spec": {
      "*": {
        "*": "[&].&1"
      }
    }
  }
]

删除重复使用jolt重复数据删除

2 个答案: