Question

我正在尝试使用jquery，ajax和php从数据库进行实时搜索。获得结果后，我想从结果中选择选项设置输入字段的值。代码返回实时搜索结果，但没有将所选选项的值设置为输入字段。

<html>
<body>
  <input type="text" id="search" placeholder="Search" />
  <div class="display"></div>

  <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
  <script>
    $(document).ready(function() {
      $("#search").keyup(function() {
        var searchid = $(this).val();
        $.ajax({
          type: "POST",
          url: "result.php",
          data: {
            search: searchid
          },
          success: function(data) {
            $(".display").html(data).show();
          }
        });
      });
    });
  </script>
  <script>
    $(document).ready(function() {
      $(".sel").click(function() {
        var value = $(this).text();
        $('#search').val(value);
      });
    });
  </script>
</body>
</html>

<?php
  $q = $_POST['search'];
  $con = mysqli_connect("localhost", "root", "", "testing");
  $query = "select name from test where name like '%$q%';";
  $result = mysqli_query($con, $query);

  while($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
  {
    $name = $row['name'];
    echo '<div class="sel">'.$name.'</div>';
  }
?>

Jquery Ajax Php实时搜索并使用所选选项填充输入文本

0 个答案: