Question

我正在使用eclipse插件，其中Project Explorer视图中存在的项目具有与项目实际路径不同的工作区名称。因此，当我尝试获取项目位置时考虑位于D:\test的项目，它指向D:\test_plugin_specific_suffix。

有没有办法从绝对路径（指向本地路径D:\test\testfile.txt）获取IFile？

我想创建一个指向特定文件的超链接，我有绝对路径。当我点击超链接上的控制台时，它应该在编辑器中打开文件。

Answer 1

您可以使用IWorkspaceRoot.findFilesForLocationURI查找与绝对路径相对应的IFile（如果您是，则可能会有多个File file = new File(....absolue path); URI location = file.toURI(); IFile[] files = ResourcesPlugin.getWorkspace().getRoot().findFilesForLocationURI(location); 使用链接）：

int main() {
    char tab = '\t';

    int input;
    bool menu = true;


    FlightSystem f;
    vector <Aircraft> allAircraftList_{};

    std::string flightNumber, airline, aircraftType, gridReference;
    int groundSpeed, altitude, heading;

    const int MaxAlt = 60000, MinAlt = 0, MaxSpeed = 800, MinHeading = 0, MaxHeading = 360;

    regex fNumber{ "([a-z]{2}([a-z])?[0-9]([0-9])?([0-9])?([0-9])?([0-9])?)" };

    do {
        std::cout << "#########################################################" << endl;
        std::cout << "#Flight Control Simulation#" << endl;
        std::cout << "#########################################################" << endl;
        std::cout << "" << endl;

        std::cout << tab << "1. Add Aircraft" << endl;
        std::cout << tab << "2. List All Aircraft" << endl;
        std::cout << tab << "3. List All Cruising Aircraft" << endl;
        std::cout << tab << "4. Number of Aircrafts in Sector" << endl;
        std::cout << tab << "5. Remove Aircraft" << endl;
        std::cout << tab << "6. Change Heading" << endl;
        std::cout << tab << "7. Get Heading" << endl;
        std::cout << tab << "8. Change Altitude" << endl;
        std::cout << tab << "9. Get Altitude" << endl;

        std::cout << "" << endl;
        std::cout << "---------------------------------------------------------" << endl;

        std::cout << "Please enter an option, between 1-9:" << endl;

        std::cin >> input;

        switch (input) {
        case:
             break;
        default:
            cout << "Your selection must be between 1 and 9" << endl;

        }
        return 0;
    } while (input != 9);
}

从绝对路径转换为IFile

1 个答案: