Question

我有一个这样的清单：

['ID|number1|number2|+|name|location','ID2|number3|number4|-|name2|location2']

列表是从字典生成的，包含字典的键。一世想改变第一个'|'进入'='。

我试过了：

keyList=[]
for item in finalDict.keys():
    keyList.append(item)

z=0
for item in keyList:
    for letter in item:
        if letter=='|':
            z+=1
            if z==1:
                letter.replace('|', '=')

但我没有收到错误或我想要的输出

Actual output:
    ['ID|number1|number2|+|name|location','ID2|number3|number4|-|name2|location2']


Desired output:
    ['ID=number1|number2|+|name|location','ID2=number3|number4|-|name2|location2']

Answer 1

改变第一个'|'进入'='

以简单的方式：

changeDetector.detach()

输出：

keyList = ['ID|number1|number2|+|name|location','ID2|number3|number4|-|name2|location2']
result = [k.replace('|', '=', 1) for k in keyList]

print(result)

['ID=number1|number2|+|name|location', 'ID2=number3|number4|-|name2|location2'] - 如果可选参数str.replace(old, new[, count])是给定，只替换第一次计数。

Answer 2

l=['ID|number1|number2|+|name|location','ID2|number3|number4|-|name2|location2']

j=[]
for i in l:
    i=i.replace("|","=",1)
    j.append(i)

print(j)

输出

['ID=number1|number2|+|name|location', 'ID2=number3|number4|-|name2|location2']

Answer 3

使用list comprehesion + regex

import re 
theList=['ID|number1|number2|+|name|location','ID2|number3|number4|-|name2|location2']

print [ re.sub(r'(ID.?)\|',r'\1=',item) for item in theList]

Python3：更改列表

3 个答案: