Question

我想创建一个迭代数组的函数，该数组包含具有名称，姓氏和年龄属性的单独对象。该函数应该使用参数“name”并在控制台中返回名称，姓氏和年龄。

我该怎么做？我已经看了一些其他的问题，但似乎无法弄清楚如何做到这一点。到目前为止我创造了这个......

var people = [
  { name: "Sue", surname: "Beckett", age: 50},
  { name: "Bill", surname: "Borough", age: 44},
  { name: "Janet", surname: "Jupp", age: 23},
  { name: "Peter", surname: "Pepper", age: 21},
  { name: "Samantha", surname: "Salad", age: 17}
];


function person(name) {
  // code here
}

person(sue)

Answer 1

只需使用Array#find() method，就像这样：

var people = [{
    name: "Sue",
    surname: "Beckett",
    age: 50
  },
  {
    name: "Bill",
    surname: "Borough",
    age: 44
  },
  {
    name: "Janet",
    surname: "Jupp",
    age: 23
  },
  {
    name: "Peter",
    surname: "Pepper",
    age: 21
  },
  {
    name: "Samantha",
    surname: "Salad",
    age: 17
  }
];

function person(name) {
  return people.find(function(p) {
    return p.name == name;
  });
}
console.log(person("Samantha"));
console.log(Object.values(person("Samantha")));

<强>演示：

string

注意：

确保在调用方法时将名称作为sue传递，只传递""而不sue将假设您有一个名为Object.values()的变量。

请注意，您可以使用console.log(Object.values(person("Samantha")));仅显示值对象属性，而不是整个对象。

简单地写一下：

var people = [ { name: "Sue", surname: "Beckett", age: 50}, { name: "Bill", surname: "Borough", age: 44}, { name: "Janet", surname: "Jupp", age: 23}, { name: "Peter", surname: "Pepper", age: 21}, { name: "Samantha", surname: "Salad", age: 17} ]; function person(name) { for (var key in people) { var person = people[key]; if (name === person.name) { console.log(person); } } } person("Sue"); // string always needs quotes: " or ' character

Answer 2

SELECT * FROM posts where id in (friendsIds)

Answer 3

使用filter：

var people = [
    { name: "Sue", surname: "Beckett", age: 50},
    { name: "Bill", surname: "Borough", age: 44},
    { name: "Janet", surname: "Jupp", age: 23},
    { name: "Peter", surname: "Pepper", age: 21},
    { name: "Samantha", surname: "Salad", age: 17}
];


function person(personName) {
    var user = people.filter(function (user) {
       return (user.name.toLowerCase() == personName.toLowerCase());
    });
    return user[0] !== undefined ? user[0] : 'not found';
}


console.log(person('sue'));

Answer 4

您可以通过检查name属性和name变量的小写值来过滤数组。

＆＃13;

function person(name) {
    people
        .filter(o => o.name.toLowerCase() === name.toLowerCase())
        .forEach(({ name, surname, age}) => {
            console.log('name:', name);
            console.log('suname:', surname);
            console.log('age:', age);
        });
}

var people = [{ name: "Sue", surname: "Beckett", age: 50 }, { name: "Bill", surname: "Borough", age: 44 }, { name: "Janet", surname: "Jupp", age: 23 }, { name: "Peter", surname: "Pepper", age: 21 }, { name: "Samantha", surname: "Salad", age: 17 }];

person('sue');

＆＃13;

Answer 5

var people = [
  { name: "Sue", surname: "Beckett", age: 50},
  { name: "Bill", surname: "Borough", age: 44},
  { name: "Janet", surname: "Jupp", age: 23},
  { name: "Peter", surname: "Pepper", age: 21},
  { name: "Samantha", surname: "Salad", age: 17}
];


function person(name) {
  people.map((data,index)=>{
    if(data.name == name)
    {
      console.log(data.name);
      console.log(data.surname);
      console.log(data.age);
      return;
    }
  })
}

person("Sue");

使用函数和参数迭代包含对象的数组

5 个答案: