在postgresql,选项数组或对象中插入jsonb数据,有效方式

时间:2017-11-06 06:31:08

标签: sql json postgresql jsonb

我有这个更新,我已经阅读了postgresql文档,但没有明确如何插入数据,一些教程选项:

1.with '{}'
2.with {}
3.with '[]'  <-- array of objects

和大多数不使用':: jsonb'之类的内容表示:

https://www.postgresql.org/docs/9.4/static/datatype-json.html

这里是我的代码:

 UPDATE customer set phones ='{  {"type": "mobile", "phone": "001001"} ,
{"type": "fix", "phone": "002002"}  }'::jsonb  
  where id ='4ca27243-6a55-4855-b0e6-d6e1d957f289';

我收到此错误:

ERROR:  invalid input syntax for type json
LINE 1: UPDATE customer set phones ='{  {"type": "mobile", "phone": ...
                                    ^
DETAIL:  Expected string or "}", but found "{".
CONTEXT:  JSON data, line 1: {  {...
SQL state: 22P02
Character: 29
我只需要记录一下手机,需要附上一个大名鼎鼎的对象吗?我的意思是对于javascript,objets数组不是一个对象,但我不知道是否在postresql的jsonb中接受

{phone:[{“type”:“mobile”,“phone”:“001001”},     {“type”:“fix”,“phone”:“002002”}]}

2 个答案:

答案 0 :(得分:1)

'{}'是postgres中的数组类型。如果您使用jsonb,请对数组使用常规'[]'

so=# select jsonb_pretty('{"phones":[ {"type": "mobile", "phone": "001001"} , {"type": "fix", "phone": "002002"} ] }');
jsonb_pretty
{
    "phones": [
        {
            "type": "mobile",
            "phone": "001001"
        },
        {
            "type": "fix",
            "phone": "002002"
        }
    ]
}
(1 row)
Time: 0.486 ms

或:

so=# select jsonb_pretty('[ {"type": "mobile", "phone": "001001"} , {"type": "fix", "phone": "002002"} ]');
jsonb_pretty
[
    {
        "type": "mobile",
        "phone": "001001"
    },
    {
        "type": "fix",
        "phone": "002002"
    }
]
(1 row)

答案 1 :(得分:1)

示例1(对象):

CREATE TABLE customer {
  contact JSONB
}
update customer
set contact = '{ "phones":[ {"type": "mobile", "phone": "001001"} , {"type": "fix", "phone": "002002"} ] }'
where id = '4ca27243-6a55-4855-b0e6-d6e1d957f289';

示例2(数组):

CREATE TABLE customer {
  phones JSONB
}
update customer
set phones = '[ {"type": "mobile", "phone": "001001"} , {"type": "fix", "phone": "002002"} ]'
where id = '4ca27243-6a55-4855-b0e6-d6e1d957f289';

注意:

  1. 我的PostgreSQL版本
select version();

PostgreSQL 11.2 (Debian 11.2-1.pgdg90+1) on x86_64-pc-linux-gnu, compiled by gcc (Debian 6.3.0-18+deb9u1) 6.3.0 20170516, 64-bit
  1. 确保键和值用双引号引起来。