Question

鉴于以下内容：

var theArray: [String] = ["uncool", "chill", "nifty", "precooled", "dandy", "cool"]

我想通过单词与关键字的相似程度对数组进行排序。

var keyWord: String = "cool"

想要的结果将是：

print// ["cool", "uncool", "precooled", ...]然后它就不再重要了。但are键或contain it应该是第一个对象。

到目前为止，我最接近的尝试是：

let _theArray = entries.sorted { element1, element2 in

     return element1.contains(keyWord) && !element2.contains(keyWord)
}

但是这导致uncool成为第一项，然后precooled和最相关的项cool甚至出现在nifty之后。

我错过了什么？非常感谢帮助。

Answer 1

您可以定义自己的相似性排序方法。请注意，我还添加了一个hasPrefix优先级，而不是仅包含关键字的那个，如果你不想要它，你可以删除它：

let theArray = ["uncool", "chill", "nifty", "precooled", "cooldaddy", "cool", "coolguy", "dandy"]
let key = "cool"

let sorted = theArray.sorted {
    if $0 == key && $1 != key {
        return true
    } else if $0.hasPrefix(key) && !$1.hasPrefix(key)  {
        return true
    } else if $0.hasPrefix(key) && $1.hasPrefix(key) && $0.count < $1.count  {
        return true
    } else if $0.contains(key) && !$1.contains(key) {
        return true
    } else if $0.contains(key) && $1.contains(key) && $0.count < $1.count {
        return true
    }
    return false
}

print(sorted)   // ["cool", "coolguy", "cooldaddy", "uncool", "precooled", "chill", "nifty", "dandy"]

Answer 2

首先，您需要衡量两个字符串的相似程度。这是一个简单的例子：

extension String {
    func equalityScore(with string: String) -> Double {
        if self == string {
            return 2     // the greatest equality score this method can give
        } else if self.contains(string) {
            return 1 + 1 / Double(self.count - string.count)   // contains our term, so the score will be between 1 and 2, depending on number of letters.
        } else {
            // you could of course have other criteria, like string.contains(self)
            return 1 / Double(abs(self.count - string.count))
        }
    }
}

完成后，您可以使用它对数组进行排序：

var theArray: [String] = ["uncool", "chill", "nifty", "precooled", "dandy", "cool"]

var compareString = "cool"

theArray.sort { lhs, rhs in
    return lhs.equalityScore(with: compareString) > rhs.equalityScore(with: compareString)
}

结果：["cool", "uncool", "precooled", "chill", "nifty", "dandy"]

如何通过与特定键的相似性对字符串数组进行排序

2 个答案: