Question

这是我的行动，当错误时，我希望retryWhen会重复当前项目，但它会从头开始重复整个过程，我尝试修改它但不会重复并抛出异常。

return Observable.fromArray(getTodayShareHolding(dd,MM,yyyy,tmpTicker, item.getId())).retryWhen(errors -> errors.flatMap(error -> Observable.timer(5, TimeUnit.SECONDS) ) );

然后我尝试修改这样的代码

@GetMapping(path = "operaion")
    public @ResponseBody void operation(@RequestParam(value = "startDate", required = true) String startDate, @RequestParam(value = "endDate", required = true) String endDate ) throws IOException, ParseException {

        List <EntityList> plist = EntityListListRepository.findByPendingDayBetweenAndIsProcessedFalseAndIsUpdatedFalse(formatDate(startDate), formatDate(endDate) );                 
        long startTime = System.currentTimeMillis();
            Observable.fromIterable(plist).concatMap( item -> {             
                Calendar cal = Calendar.getInstance();                                  
                cal.setTime(item.getPendingDay());
                Integer yyyy = cal.get(Calendar.YEAR);
                Integer MM = cal.get(Calendar.MONTH)+1;
                Integer dd = cal.get(Calendar.DAY_OF_MONTH);
                String tmpId = item.getTmpId().toString();
                Integer delayCheck = item.getTmpId();
                Integer delayMiniSec = 0;

                if(delayCheck >= 70000) {
                        delayMiniSec = 0;

                }
                Date currentTime = new Date();      
                System.out.println("Step1 ::{ : "+dd+"/"+MM+"/"+yyyy+"@"+tmpId+" id = ["+item.getId()+"] } startInsert time = "+currentTime);
                return Observable.fromArray(fetchList(dd,MM,yyyy,tmpId, item.getId()))

            }).retryWhen(errors -> errors.flatMap(error -> Observable.timer(5, TimeUnit.SECONDS) ) );
            .subscribe(System.out::println);

它会在开始发生时重复整个过程，有人给我一些建议吗？

更新：或者我尝试下面这样的事情？ http://aspects.jcabi.com/annotation-retryonfailure.html

Rxjava，发生错误时重复现有项

0 个答案: