Question

我设置了我的本地主机，我已经准备好了所有相关文件。我运行php运行sql查询，它返回NULL值。但它不应该。我通过浏览器访问链接目录。

有人能指出我的返回方向，为什么它会返回NULL？我运行SQL查询，并在我的phpmyAdmin

上正常工作

<?php
header('Content-Type: application/json');
define('DB_HOST', '127.0.0.1');
define('DB_USERNAME', 'myusername');
define('DB_PASSWORD', 'Ihavenopassword');
define('DB_NAME', 'mytablename');
$mysqli = new mysqli(DB_HOST, DB_USERNAME, DB_PASSWORD, DB_NAME);
//$conn = mysqli_connect($db_host, $db_user, $db_pass, $db_name);
if(!$mysqli){
    die("Connection failed: " . $mysqli->error);
}

//query to get data from the table
$query = sprintf("SELECT playerid, score FROM score ORDER BY playerid");

//execute query
$result = $mysqli->query($query);


//loop through the returned data
$data = array();
foreach ($result as $row) {
    $data[] = $row;
}

//free memory associated with result
$result->close();

//close connection
$mysqli->close();

//now print the data
print json_encode($data);

Answer 1

$result不是您所期望的。您需要使用fetch_assoc获取每个项目，例如：

//loop through the returned data
$data = array();
while ($row = $result->fetch_assoc()) {
    $data[] = $row;
}

Null从localhost php编码返回

1 个答案: