Question

假设我有两个不同的模型和表，名为public class MyApp extends Application { public static boolean isDebuggable; public void onCreate() { super.onCreate(); isDebuggable = (0 != (getApplicationInfo().flags & ApplicationInfo.FLAG_DEBUGGABLE)); FirebaseCrash.setCrashCollectionEnabled(!isDebuggable); } }和user。

如您所知，laravel使用company模型来管理身份验证。但是因为我有两种不同的型号我想要分别管理它们。

我使用的是laravel 5.4，我不知道怎么做。

Answer 1

如果您正在谈论多个身份验证系统，那么您必须创建多个警卫才能实现这一目标。

对同一个问题有很好的答案。

Can anyone explain Laravel 5.2 Multi Auth with example

它在Laravel 5.2上，但它可以在Laravel 5.4上轻松实现。

创建扩展可验证类的模型 App \ Company 。此模型将作为用户模型工作，公司保护（下一步）

namespace App;

use Illuminate\Notifications\Notifiable;
use Illuminate\Foundation\Auth\User as Authenticatable;

class Company extends Authenticatable
{

    use Notifiable;

    /**
     * The attributes that are mass assignable.
     *
     * @var array
     */
    protected $fillable = [
        'name', 'email', 'password',
    ];

    /**
     * The attributes that should be hidden for arrays.
     *
     * @var array
     */
    protected $hidden = [
        'password', 'remember_token',
    ];

}

为模型 App \ Company 创建一名警卫和提供者。

// Authenticating guards and providers

'guards' => [
    'web' => [
        'driver' => 'session',
        'provider' => 'users',
    ],
    'api' => [
        'driver' => 'token',
        'provider' => 'users',
    ],
    'company' => [
        'driver' => 'session',
        'provider' => 'company',
    ],
],

// Providers 

'providers' => [
    'users' => [
        'driver' => 'eloquent',
        'model' => App\User::class,
    ],
    'company' => [
        'driver' => 'eloquent',
        'model' => App\Company::class,
    ]
],

现在您可以根据不同的警卫找到用户。

$user = Auth::guard('company')->user();
// Or...
$user = auth()->guard('company')->user();
dd($user);

现在为公司 App \ Http \ Controllers \ Auth \ CompanyLoginController 创建Auth控制器，与 Auth \ LoginController 相同。指定 $ redirectTo 和后卫

//Auth\ComapnyLoginController.php

protected $redirectTo = '/comapany';
protected $guard = 'comapany';

public function showLoginForm()
{
    if (view()->exists('auth.authenticate')) {
        return view('auth.authenticate');
    }

    return view('comapany.auth.login');
}

现在为用户创建登录表单 - company.auth.login视图与用户的登录表单相同。

现在创建路线

//Login Routes...
Route::group(['prefix'=>'company', 'middleware'=>'company'], function(){
    Route::get('/login','Auth\CompanyLoginController@showLoginForm');
    Route::post('/login','Auth\CompanyLoginController@login');
    // ...
    // rest of the company dashboard and other links
    // ...
    Route::get('/logout','Auth\CompanyLoginController@logout');
});

为公司创建中间件

class RedirectIfNotCompany
{
    /**
     * Handle an incoming request.
     *
     * @param  \Illuminate\Http\Request  $request
     * @param  \Closure  $next
     * @param  string|null  $guard
     * @return mixed
     */
    public function handle($request, Closure $next, $guard = 'company')
    {
        if (!Auth::guard($guard)->check()) {
            return redirect('/');
        }

        return $next($request);
    }
}

并将其注册到kernal.php

protected $routeMiddleware = [
    'company' => \App\Http\Middleware\RedirectIfNotCompany::class,
];

这就是你需要的一切。以守卫名称访问用户

Auth::guard('company')->user()

laravel 5.4中用于身份验证的两种不同模型

1 个答案: