我理解合并排序是如何工作的,但是当我尝试在python中实现时,我认为我仍然对如何在堆栈上实现工作感到困惑。我有一个名为merge_sorted_list的函数,用于合并两个排序列表和一个名为merge_sort1和merge_sort2的函数,这些函数用于递归过程。 " merge_sort1"和" merge_sort2"非常相似,但只有merge_sort2给出了正确的答案。看起来merge_sort1没有在堆栈的每个级别获取返回值。谁能告诉我merge_sort1和merge_sort2之间的评价有什么不同呢?
def merge_sorted_list(list1,list2):
if(len(list1) == 0 or len(list2) == 0):
print('input error')
return;
i = 0
j = 0
k = 0
list_merge = [0]*(len(list1) + len(list2))
while(i < len(list1) and j < len(list2)):
if (list1[i] < list2[j]):
list_merge[k] = list1[i]
i += 1
else:
list_merge[k] = list2[j]
j += 1
k += 1
while(i < len(list1)):
list_merge[k] = list1[i]
i += 1
k += 1
while (j < len(list2)):
list_merge[k] = list2[j]
j += 1
k += 1
return(list_merge)
def merge_sort1(mylist):
print("splitting ",mylist)
if (len(mylist) > 1):
mid = len(mylist)//2
merge_sort1(mylist[:mid])
merge_sort1(mylist[mid:])
# lefthalf = mylist[:mid]
# righthalf = mylist[mid:]
# merge_sort1(lefthalf)
# merge_sort1(righthalf)
mylist[:] = merge_sorted_list(mylist[:mid],mylist[mid:])
print("merging result ",mylist)
return mylist
def merge_sort2(mylist):
print("splitting ",mylist)
if (len(mylist) > 1):
mid = len(mylist)//2
# merge_sort2(mylist[:mid])
# merge_sort2(mylist[mid:])
lefthalf = mylist[:mid]
righthalf = mylist[mid:]
merge_sort2(lefthalf)
merge_sort2(righthalf)
mylist[:] = merge_sorted_list(lefthalf,righthalf)
print("merging result ",mylist)
return mylist
如果我们尝试merge_sort1([4,67,3,3,2,6]),输出将是
('splitting ', [4, 67, 3, 3, 2, 6])
('splitting ', [4, 67, 3])
('splitting ', [4])
('splitting ', [67, 3])
('splitting ', [67])
('splitting ', [3])
('merging result ', [3, 67])
('merging result ', [4, 67, 3])
('splitting ', [3, 2, 6])
('splitting ', [3])
('splitting ', [2, 6])
('splitting ', [2])
('splitting ', [6])
('merging result ', [2, 6])
('merging result ', [2, 3, 6])
('merging result ', [3, 2, 4, 6, 67, 3])
merge_sort2([4,67,3,3,2,6])的输出将是
('splitting ', [4, 67, 3, 3, 2, 6])
('splitting ', [4, 67, 3])
('splitting ', [4])
('splitting ', [67, 3])
('splitting ', [67])
('splitting ', [3])
('merging result ', [3, 67])
('merging result ', [3, 4, 67])
('splitting ', [3, 2, 6])
('splitting ', [3])
('splitting ', [2, 6])
('splitting ', [2])
('splitting ', [6])
('merging result ', [2, 6])
('merging result ', [2, 3, 6])
('merging result ', [2, 3, 3, 4, 6, 67])
非常感谢
答案 0 :(得分:1)
mylist[:mid]
返回列表。在list_sort1
中,您(尝试)对此列表进行排序,然后立即将其丢弃。稍后,您正在使用mylist[:mid]
的第二个(未修改的)实例。等mylist[mid:]
。另一方面,在第二个版本中,您将mylist[:mid]
等的结果分配给变量,因此不会丢弃对它们进行排序的结果。