preg_replace错误

Question

我有一个需要在大型sting中替换的实体数组，但只有第一次出现（这就是我使用preg_replace而不是str_replace的原因），例如：

$entities = array();
$entities[0] = 'string1';
$entities[1] = 'string2';
$entities[2] = 'string2';
$entities[3] = 'Error String ('; ## this is the one that errors because of the bracket
$entities[4] = 'string4';
$entities[5] = 'string5';

foreach ($entities as $entity) {
    $new_article = preg_replace('/' . $entity . '/', '##' . $key, $new_article, 1);
}

我收到以下错误：

Warning (2): preg_replace() [function.preg-replace]: Compilation failed: missing ) at offset XX

使括号转义的最佳方法是什么，并且还可以转义可能在正则表达式中使用的任何其他字符。

由于

Answer 1

您需要preg_quote

Answer 2

你必须逃避大括号。您可以使用preg_quote()。

执行此操作

$entity = preg_quote($entity, '/');

http://www.php.net/manual/en/function.preg-quote.php

Answer 3

您可以使用preg_quote

$entities = array();
$entities[0] = 'string1';
$entities[1] = 'string2';
$entities[2] = 'string2';
$entities[3] = 'Error String ('; ## this is the one that errors because of the bracket
$entities[4] = 'string4';
$entities[5] = 'string5';

foreach ($entities as $entity) {
    $new_article = preg_replace('/' . preg_quote($entity) . '/', '##' . $key, $new_article, 1);
}