Question

我需要将数量解析为十进制，将货币代码解析为字符串。

输入字符串

302 600.00 RUB
10 000.00 USD

模式是

QUANTITY-＆GT;空间 - ＆GT; CURRENCYCODE
两个DECIMAL DIGITS
空间为千位分隔符，点为小数点分隔符

Answer 1

这未经过测试，但你可以做这样的事情。

string text = "302 600.00 RUB";
decimal amount;
string type;

var lastspace = text.lastIndexOf(" ");    
decimal.TryParse(text.substring(0, lastspace - 1), out amount);
type = text.substring(lastspace + 1);

希望这有帮助。

Answer 2

using System.Text.RegularExpressions;

[...]

string sInput = "302 10 600.00 RUB";
// string sInput = "302 600.00 RUB";
// string sInput = "10 000.00 USD";

var rgmResult = Regex.Match(sInput, @"^(?<qty>\d+) (?<price>\d{1,3}( \d{3})*\.\d{2}) (?<cur>[A-Z]{3})$");
string sQuantity = rgmResult.Groups["qty"].Value;
string sPrice = rgmResult.Groups["price"].Value;
string sCurrency = rgmResult.Groups["cur"].Value;

Answer 3

您可以将正则表达式与累加器一起使用，自定义 NumberFormat

string pattern = @"(?<decimal>[0-9]{0,3}(\s[0-9]{3})*(.[0-9]+){0,1})\s" +
                 @"(?<currency>[a-zA-Z]+){1}";

string input = "302 600.00 RUB\r\n10 000.00 USD"; 

// Get text that matches regular expression pattern.
MatchCollection matches = Regex.Matches(input, pattern, RegexOptions.IgnoreCase);

NumberFormatInfo format = new NumberFormatInfo();
format.NumberGroupSeparator = " ";
format.NumberDecimalSeparator = ".";
format.NumberDecimalDigits = 2;

Dictionary<string, decimal> dictionary = new Dictionary<string, decimal>();
foreach (Match match in matches)
{
    dictionary.Add(match.Groups["currency"].Value, Decimal.Parse(match.Groups["decimal"].Value, format));      
}
if (dictionary.Count > 0)
{
    foreach (KeyValuePair<string, decimal> item in dictionary)
    {
        Console.WriteLine("Currency : {0} Amount: {1}", item.Key, item.Value);
    }
}

输出是：

Currency : RUB Amount: 302600,00
Currency : USD Amount: 10000,00

需要建议解析字符串中的十进制值

3 个答案: