Question

我正忙于一个小测试案例，并希望自己制作路线。所以当我执行www.domain.com/users时，我想用一个名为index的方法创建一个对象。所以我可以将数据从索引方法传递给视图/模板。

如何在路线中动态获取$class->index()？

Router::route('/users' , 'UsersController@index');
Router::execute($_SERVER['REQUEST_URI']);

class Router {

    private static $routes = array();

    private function __construct() {}
    private function __clone() {}

    public static function route($pattern, $callback) {
        $pattern = $pattern;
        self::$routes[$pattern] = $callback;
    }

    public static function execute($url) {
        foreach (self::$routes as $pattern => $callback) {
            if($pattern==$url){
                $callback = explode('@' , $callback);

                $fullclass = __NAMESPACE__ . '\\Controllers\\' . $callback[0];
                $class = new $fullclass;
                ---- Here is my problem ----
                $method = "index()";
                $class->$method.'()';
            }
        }
    }
}

Answer 1

您的代码可能会被重写为：

$method = "index";
$class->$method();

另请看这里：

http://php.net/manual/en/function.call-user-func-array.php

// Call the $foo->bar() method with 2 arguments
$foo = new foo;
call_user_func_array(array($foo, "bar"), array("three", "four"));

简单的动态路由器获取方法不起作用

1 个答案: