我无法从iPhone地址簿中获取电话号码。
如果该号码不包含国家/地区代码前缀(如+45),则没有问题,如果有,我的应用程序崩溃...
这是一个已知问题吗?我一直无法找到任何关于它的东西......
由于
编辑:
我得到这样的电话号码:
-(void)getContact
{
ABPeoplePickerNavigationController *pp = [[ABPeoplePickerNavigationController alloc] init];
pp.displayedProperties = [NSArray arrayWithObject:[NSNumber numberWithInt:kABPersonPhoneProperty]];
pp.peoplePickerDelegate = self;
[self presentModalViewController:pp animated:YES];
[pp release];
}
- (void)peoplePickerNavigationControllerDidCancel:(ABPeoplePickerNavigationController *)peoplePicker {
// assigning control back to the main controller
[self dismissModalViewControllerAnimated:YES];
}
- (BOOL)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker shouldContinueAfterSelectingPerson:(ABRecordRef)person {
return YES;
}
-(BOOL)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker shouldContinueAfterSelectingPerson:(ABRecordRef)person property:(ABPropertyID)property identifier:(ABMultiValueIdentifier)identifier {
ABMultiValueRef phoneProperty = ABRecordCopyValue(person,property);
saveString = (NSString *)ABMultiValueCopyValueAtIndex(phoneProperty,identifier);
saveString = [saveString stringByReplacingOccurrencesOfString:@" " withString:@""];
nummerTextField.text = saveString;
}
答案 0 :(得分:0)
如何检索地址簿对象,一旦检索到它,如何处理它以从中获取数字。我使用下面显示的代码执行与您提到的相同的操作并准确提取数字
ABRecordRef person = ABAddressBookGetPersonWithRecordID(appDelegate.addressBook, contactId);
ABMultiValueRef multiValue = ABRecordCopyValue(person, kABPersonPhoneProperty);
NSArray *allNumbers = (NSArray *)ABMultiValueCopyArrayOfAllValues(multiValue);
NSMutableDictionary *filteredNumbers = [NSMutableDictionary new];
if([allNumbers count] > 0) {
for(int contactIndex = 0; contactIndex < [allNumbers count]; contactIndex++) {
NSString *contactValue = (NSString *)ABMultiValueCopyLabelAtIndex(multiValue, contactIndex);
if(!([contactValue isEqualToString:@"_$!<WorkFAX>!$_"] || [contactValue isEqualToString:@"_$!<HomeFAX>!$_"] || [contactValue isEqualToString:@"_$!<Pager>!$_"])) {
if([[contactValue substringWithRange:contactLabelCharacterCustom] isEqualToString:@"_$"])
typeOfContact = [contactValue substringWithRange:contactLabelCharacter];
else
typeOfContact = [contactValue substringWithRange:(NSRange){0,1}];
NSString *value = (NSString *)ABMultiValueCopyValueAtIndex(multiValue, contactIndex);
[filteredNumbers setValue:typeOfContact forKey:value];
[value release];
value = nil;
}
[contactValue release];
contactValue = nil;
}
}
我相信它会对你有帮助。
干杯
答案 1 :(得分:0)
这解决了我的问题。希望有人觉得它有用。
ABMultiValueRef multiValue = ABRecordCopyValue(person, property);
NSString *number = (NSString *)ABMultiValueCopyValueAtIndex(multiValue, ABMultiValueGetIndexForIdentifier(multiValue, identifier));
// Error was here: NSString *value = (NSString *)ABMultiValueCopyValueAtIndex(multiValue, contactIndex);
//Copy the number etc before cleaning everything up
saveString = number;
saveString = [saveString stringByReplacingOccurrencesOfString:@" " withString:@""];
nummerTextField.text = saveString;
[number release];
CFRelease(multiValue);