Question

我如何检查进程是否正在运行，如果它正在运行，那么echo＆＃34;进程正在运行＆＃34;并防止他们使用该过程直到完成。我有这段代码，但我不能让它在回声之后不允许它们使用该过程：

#!/bin/bash
SERVICE=EXAMPLE
if ps ax | grep -v grep | grep -v grep | grep $SERVICE > /dev/null
then
echo -e ""
echo -e "${LIGHTRED}[!] ${WHITE}Please wait till process is finished."
fi

Answer 1

似乎你想写一个循环，而不是一个if语句。你可能想在检查条件之间睡一会儿。

#!/bin/bash

SERVICE=EXAMPLE

while ps ax | grep -v grep | grep "$SERVICE" > /dev/null
do
    echo
    echo -e "${LIGHTRED}[!] ${WHITE}Please wait till process is finished."
    sleep 60
fi

如果你有pgrep：

，情况会更简单

while pgrep "$SERVICE" >/dev/null

（如果while pgrep -q "$SERVICE"的实施支持，则更简单pgrep。）

当没有匹配的过程（已经完成或尚未开始）时，那么脚本不会产生任何输出。如果你想在这种情况下得到一些输出，然后你可以像这样重做：

while true
do
    if pgrep "$SERVICE" > /dev/null; then
        echo
        echo -e "${LIGHTRED}[!] ${WHITE}Please wait till process is finished."
        sleep 60
    else
        echo "Process '$SERVICE' not running"
        break
    fi
fi

仅打印消息一次，并等待该过程不再运行：

is_running() {
    pgrep "$SERVICE" > /dev/null
}

if is_running; then
    echo -e "${LIGHTRED}[!] ${WHITE}Please wait till process is finished."
    while true; do
        sleep 60
        is_running || break
    done
else
    echo "Process '$SERVICE' not running"
fi

Answer 2

另一种解决方案

#!/bin/bash
tput civis # hide cursor
until ! ps -ef | grep "$SERVICE" | grep -v "grep" > /dev/null; do
    while ps -ef | grep "$SERVICE" | grep -v "grep" > /dev/null; do
        echo -en "\r${LIGHTRED}[!] ${WHITE}Please wait till process is finished."
    done
    printf "\r%80s" "" # clear line
    echo -en "\rProcess '$SERVICE' is completed!\n"
done
tput cnorm # show cursor again

如果您同时拥有多个服务实例，此解决方案也很有用。

检查进程是否在bash脚本中运行

2 个答案: