Question

我是编码的新手，我想知道是否有办法简化这个：

if "!" in name or "$" in name or "%" in name or "^" in name or "&" in name or "*" in name or "(" in name or ")" in name or "_" in name or "-" in name or "+" in name or "=" in name:
points = points + 1

谢谢

Answer 1

您可以使用正则表达式：

 var btn = document.createElement("button");
    var txt = document.createTextNode("Bought");
    var div = document.getElementById("div");

    btn.appendChild(txt);

    $(btn).attr("id", "Btn1");
    $(btn).addClass("btn btn-primary custom"); //add custom to allow hover css
    $(btn).html("Click me");
    
    div.appendChild(btn);

Answer 2

withUnsafeMutablePointer(to: &nc) {
    dgetrf_($0, $0, &matrix, $0, &ipiv, &info)
}

Answer 3

您可以编写一个简单的函数来实现此目的。

def is_included(characters, sentence):
    for character in characters:
        if character in sentence:
            return True
    return False

正如mgilson所说，您也可以使用any关键字。但是，由于您不熟悉编程，我建议您学习关键字的算法。

简化python中的列表？

3 个答案: