Question

对于我的C类，我必须编写一个程序来计算文件中每个数字（0-9）的频率。我已经用Java编写了代码但是无法将其翻译成C.任何帮助都将受到赞赏。我将在下面添加我所拥有的内容。文本文件的一部分被添加到代码的末尾以显示它的外观，随机的符号和数字字符串。

 #include<stdio.h>
    #define m 100
    #define n 60

    void main() {
    char file_name[m]; FILE *input_file;
    char symb, symb0, symb1, symb2, symb3, symb4, symb5, symb6;
    char symb7, symb8, symb9;
    int i;

    printf("Enter name of the input file: "); scanf("%s", file_name);
    input_file = fopen(file_name, "r");

    while (input_file == NULL) {
    printf("Error: There is no file \"%s\"\n", file_name);
    printf("Enter file name (or \".\" to exit): "); scanf("%s", file_name);
    if (strcmp(file_name, ".") == 0) return;
    input_file = fopen(file_name, "r");}

    //read each char of the file till the end
    while ((symb=getc(input_file))!=EOF){
             // if the char is between '0'-'9' print it
            if(symb >= '0' && symb <='9'){
                //printf("%c", symb);
                switch(symb){
                    case '0' :
                    symb0++;
                    break;
                    case '1' :
                    symb1++;
                    break;
                    case '2' :
                    symb2++;
                    break;
                    case '3' :
                    symb3++;
                    break;
                    case '4' :
                    symb4++;
                    break;
                    case '5' :
                    symb5++;
                    break;
                    case '6' :
                    symb6++;
                    break;
                    case '7' :
                    symb7++;
                    break;
                    case '8' :
                    symb8++;
                    break;
                    case '9' :
                    symb9++;
                    break;
                }
                            printf("%c", symb3);
                }
    }

    printf("\n-= Count the Thisles in =-");

    fclose(input_file);
    }
    //...1..1.'`.1.........2..2..2...../\......./%%%%\/%%\.3...4..
    //......'............../\........./%%\../\./%%%%%%/\%%\33..4..
    //...'.../\.........../%%\.../\.../%%\./%%\%/\%/\/%%\%/\......
    //.'..../%%\./\......./%%\../%%\./%%%%\/%%\/%%\%%\%%%/%%\.55..

Answer 1

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lineparts = line.split("\t+");

如何计算文件中每个数字的频率？

1 个答案: