反向地理编码; JSON根据可用数据不断变化

时间:2011-01-17 07:11:47

标签: php reverse-geocoding

你好 我能够根据纬度/经度值将地理编码反转到某个位置。 但我的问题是我只需要国家和城市名称,没有别的。

谷歌提供的json数据会根据可用数据不断变化。有时会有一个位置字符串,但对于某些纬度/经度,没有位置信息。是否有经验法则或某些包装类可以从所有可能的json字符串中提取城市和国家?

例如http://maps.google.com/maps/geo?q=24.487148563173424,-78.046875&output=json给了我

{
  "name": "24.487148563173424,-78.046875",
  "Status": {
    "code": 200,
    "request": "geocode"
  },
  "Placemark": [ {
    "id": "p1",
    "address": "Central Andros, The Bahamas",
    "AddressDetails": {
   "Accuracy" : 3,
   "Country" : {
      "CountryName" : "The Bahamas",
      "CountryNameCode" : "BS",
      "SubAdministrativeArea" : {
         "SubAdministrativeAreaName" : "Central Andros"
      }
   }
},
    "ExtendedData": {
      "LatLonBox": {
        "north": 24.6312368,
        "south": 24.3062499,
        "east": -77.7177462,
        "west": -78.2299838
      }
    },
    "Point": {
      "coordinates": [ -77.9738650, 24.4688482, 0 ]
    }
  } ]
}

http://maps.google.com/maps/geo?q=47.33882269482199,-100.634765625&output=json给我的地方

{
  "name": "47.33882269482199, -100.634765625",
  "Status": {
    "code": 200,
    "request": "geocode"
  },
  "Placemark": [ {
    "id": "p1",
    "address": "11445 471st Ave NE, McClusky, ND 58463, USA",
    "AddressDetails": {
   "Accuracy" : 8,
   "Country" : {
      "AdministrativeArea" : {
         "AdministrativeAreaName" : "ND",
         "SubAdministrativeArea" : {
            "Locality" : {
               "LocalityName" : "McClusky",
               "PostalCode" : {
                  "PostalCodeNumber" : "58463"
               },
               "Thoroughfare" : {
                  "ThoroughfareName" : "11445 471st Ave NE"
               }
            },
            "SubAdministrativeAreaName" : "Sheridan"
         }
      },
      "CountryName" : "USA",
      "CountryNameCode" : "US"
   }
},
    "ExtendedData": {
      "LatLonBox": {
        "north": 47.3307737,
        "south": 47.3244785,
        "east": -100.6025856,
        "west": -100.6089256
      }
    },
    "Point": {
      "coordinates": [ -100.6089257, 47.3276298, 0 ]
    }
  } ]
}

是否有一些标准程序可以获取城市和国家名称? 我正在穿越json,试图处理gogole向我投掷的不同格式。

由于

1 个答案:

答案 0 :(得分:0)

您可以尝试寻找合适的解析器来提取该信息吗?

修改

http://www.devshed.com/c/a/PHP/Parsing-Google-Maps-API-using-PHP-and-JSON-2348127/

我相信这对你的解析器是一个很好的阅读