我有以下查询
string updateReq = "UPDATE Student SET Student.ID_Request =
Request.ID_Request FROM Request where Student.St_Code=Request.St_Code INNER JOIN Request ON Student.ID_Request =
Request.ID_Request";
但是当我执行此操作时,我收到此错误:
FROM子句中的“Request”和“Request”对象具有相同的公开名称。使用相关名来区分它们。
我该如何解决这个问题?
我试图在临时表中选择记录,但它不起作用或者我做错了
string select = "SELECT * INTO #TempTable FROM Student s where ID_Request IS NULL";
string updateReq = "UPDATE TempTable SET s.ID_Request = Request.ID_Request FROM Request where Student.St_Code=Request.St_Code INNER JOIN Request ON Student.ID_Request = Request.ID_Request";
当我执行这些字符串时,我得到相同的错误
答案 0 :(得分:1)
据推测,您打算这个查询:
UPDATE Student
SET ID_Request = r.ID_Request
FROM Student s JOIN
Request r
ON s.St_Code = r.St_Code ;
答案 1 :(得分:0)
尝试使用使用' AS'
完成的别名即
SELECT *
FROM table1 AS first
INNER JOIN table1 AS second ON second.col = first.col;