Question

以下是我需要查询的数据的子集。 “我需要做的就是采取任何匹配但仍有差异的路由并连接值在一个单独的专栏中。前后见下文。有关如何的任何建议这样做会很棒吗？

这是我的疑问：

select mcrp27, irkitl
from f0006
join f3003
on mcmcu = irmcu 
where mcrp27 <> ' '
and irmmcu = ' 20101556'
order by mcrp27

在：

ROUTING DEPT
======= =======  
R335700 1
R335800 1
R335900 1
R336000 1
R336100 1
R336200 1
R336300 1
R336500 1
R435500 1
R435501 1
R435600 1
R435700 1
R436400 1
R336100 2
R336200 2
R336300 2
R436400 2
R436400 3
R335300 5
R335300 6
R331400 7
R331500 7
R331600 7
R331900 7
R332100 7
R332200 7
R332400 7
R332500 7
R332600 7
R332700 7

后：

R335700 1   
R335800 1   
R335900 1   
R336000 1   
R336100 1   2   
R336200 1   2   
R336300 1   2   
R336500 1   
R435500 1   
R435501 1   
R435600 1   
R435700 1   
R436400 1   2   3
R335300 5   6   
R331400 7   
R331500 7   
R331600 7   
R331900 7   
R332100 7   
R332200 7   
R332400 7   
R332500 7   
R332600 7   
R332700 7

Answer 1

由于每个ROUTING可以有任意数量的DEPT，并且SQL查询只能返回先前已知数量的列，因此我建议以逗号分隔的字符串返回DEPT。所以你有两列：ROUTING和DEPTS。

select routing, listagg(dept, ',') within group (order by dept) as depts
from mytable
group by routing
order by routing;

SQL查询在列中查找重复？

1 个答案: