考虑我有一个JSON数据:
{
"entities":[
{
"republish": false,
"OrgID": "",
"createdby": "730",
"questions": [
{
"sequence": "5",
"QuestionId": "57BB6DDC-A90A-10EE-E224-EC658A825871",
"metadata": [
{
"key": "Group",
"value": 0
},
{
"key": "Part",
"value": "0"
}
]
},
{
"sequence": "4",
"QuestionId": "57BB6DDC-A90A-10EE-E224-EC658A825871",
"metadata": [
{
"key": "Group",
"value": 1
},
{
"key": "Part",
"value": "A"
}
]
},
{
"sequence": "3",
"QuestionId": "57BB6DDC-A90A-10EE-E224-EC658A825871",
"metadata": [
{
"key": "Group",
"value": 1
},
{
"key": "Part",
"value": "B"
}
]
}
]
}
]
}
正如您所看到的,我有一个可用的问题列表,在每个问题中,我都有一个包含键值对的元数据。
以上示例演示,我有3个问题,其中2个问题,元数据键值是"组1"。
现在我想做的是将问题与相同的键值对结合起来并将其视为一个。
所以在我的最后一个案例中,我将有2个问题而不是3个问题。在这个问题中,将有两个单独的问题。
我希望使用Linq查询来实现这一点。如果可能的话,如果需要,请使用Newtonsoft进行解析。我长期坚持这一点。
我做过的事情:
public virtual HttpResponseMessage AddQuestionsToStandardMaster(TaxonomyMetaData objQuestion)
{
List<ResponseEntity> objResponseList = new List<ResponseEntity>();
try
{
if (ModelState.IsValid)
{
foreach (var objEntity in objQuestion.Entities)
{
EntityResponse objentityresponse = new EntityResponse();
ResponseEntity objResponse = new ResponseEntity();
}
List<Question> objQuestionList = new List<Question>();
if (objEntity.Questions.Length > 0)
{
foreach (var item in objEntity.Questions)
{
int questionTypeid = 0;
dynamic objQuestionJson = JObject.Parse(item.ToString())
}
}
}
Question objCurrentQuestion = new Question();
Question objQuestionforDelete = new Question();
JObject itemToParese = new JObject();
string SingleQuestionJson = objQuestionJson.GetValue("QuestionData").ToString();
string questionstem = "";
Regex rgx = new Regex("/\'");
objCurrentQuestion.Sequence = Convert.ToInt32(objQuestionJson.GetValue("sequence"));
objCurrentQuestion.tag = objQuestionJson.tag.ToObject<JToken[]>(); ;
objCurrentQuestion.metadata = objQuestionJson.metadata.ToObject<JToken[]>();
objCurrentQuestion.SingleQuestionJson = rgx.Replace(SingleQuestionJson, "'");
objCurrentQuestion.QuestionsType = questionTypeid;
objCurrentQuestion.QuestionsId = new Guid(objQuestionJson.GetValue("QuestionId").ToString());
objCurrentQuestion.VersionNo = Convert.ToInt32(objQuestionJson.GetValue("VersionNo"));
objCurrentQuestion.DisplayQuestionId = Convert.ToString(objQuestionJson.GetValue("DisplayQuestionId"));
objCurrentQuestion.OriginalQuestionId = Convert.ToString(objQuestionJson.GetValue("OriginalQuestionId"));
objCurrentQuestion.PassageText = Convert.ToString(objQuestionJson.GetValue("passage_text"));
objCurrentQuestion.PassageCode = Convert.ToString(objQuestionJson.GetValue("passage_id"));
objCurrentQuestion.PassageTitle = Convert.ToString(objQuestionJson.GetValue("passage_title"));
objCurrentQuestion.IsPublished = Convert.ToByte(true);
objCurrentQuestion.ProductId = objEntity.ProductID;
foreach (var metadata in objCurrentQuestion.metadata)
{
switch (metadata["key"].ToString())
{
case "Group":
objCurrentQuestion.Group = Convert.ToInt32(metadata["value"].ToString());
break;
case "Part":
objCurrentQuestion.Part = metadata["value"].ToString();
break;
}
}
objQuestionList.Add(objCurrentQuestion);
int counter = 1;
//Here I get the data in a group which needs to coverted to JSOn and then replace the original JSON data with this. But I know this is irrelevant to what we need to achieve.
var yui = objQuestionList.Where(tma => tma.Group == counter).Select(t => t).GroupBy(s => new { s.Group }).Where(p => p.Count() > 1).ToList();
//After proper conversion I need to enter this data to a database.
答案 0 :(得分:0)
我有点不清楚你的意思是什么
将问题与相同的键值对结合起来并将其视为一个
但是,您可以通过JSON将元组分组到元数据组中,您可以根据需要自定义选择。
var text = @"{
""entities"":[
{
""republish"": false,
""OrgID"": """",
""createdby"": ""730"",
""questions"": [
{
""sequence"": ""5"",
""QuestionId"": ""57BB6DDC-A90A-10EE-E224-EC658A825871"",
""metadata"": [
{
""key"": ""Group"",
""value"": 0
},
{
""key"": ""Part"",
""value"": ""0""
}
]
},
{
""sequence"": ""4"",
""QuestionId"": ""57BB6DDC-A90A-10EE-E224-EC658A825871"",
""metadata"": [
{
""key"": ""Group"",
""value"": 1
},
{
""key"": ""Part"",
""value"": ""A""
}
]
},
{
""sequence"": ""3"",
""QuestionId"": ""57BB6DDC-A90A-10EE-E224-EC658A825871"",
""metadata"": [
{
""key"": ""Group"",
""value"": 1
},
{
""key"": ""Part"",
""value"": ""B""
}
]
}
]
}
]
}";
var json = JObject.Parse(text);
var groupedData = from entity in json["entities"]
from question in entity["questions"]
group question by question["metadata"][0]["value"] into questionGroup
select questionGroup;
foreach (var data in groupedData)
{
Console.WriteLine("_____________________");
Console.WriteLine("Group");
Console.WriteLine(data.Key);
foreach (var question in data)
{
Console.WriteLine(question["QuestionId"]);
}
Console.WriteLine("_____________________");
}
如果“Group”并不总是数组中的第一项,那么
question["metadata"].First(md => md.Value<string>("key") == "Group")["value"]
得到它。