Question

提示：“写一个程序来对着电脑玩猪游戏。每一个回合，当前玩家都会滚动一对骰子并累积积分。目标是在你之前达到100分或更多分对手呢。（为了测试目的，使用30而不是100分）如果在任何转弯，玩家滚动1，所有积累的所有积分都将被没收并控制骰子移动到其他玩家。如果玩家在一个回合中滚动两个1，则玩家将失去所有积分到目前为止累积的都被没收并且控制权移动到另一个玩家。玩家可以每次掷骰后自愿翻转骰子的控制权。因此玩家必须决定滚动再次（成为一头猪）并冒险失去分数，或放弃对骰子的控制，可能允许骰子其他球员获胜。计算机将翻转硬币来选择第一个玩家“

我的问题：我得到的程序输出计算机或播放器首先基于硬币翻转。但是，我如何实际提示程序运行首先选择启动的人的方法，然后在每个回合结束时如何在计算机和玩家之间切换？顺便说一句，我知道这段代码不完整，但我希望我的问题有道理。

到目前为止

代码：

import java.util.*;
public class NavaiPigGame
{
   public static final int POINT = 30;
   public static final int FORFEIT_POINTS = 20;
   public static void main(String[] args)
   {
      Scanner input = new Scanner(System.in);
      Random rand = new Random();
      play(rand,input);
   }
   // desription of game
   public static void description()
   {
      System.out.println("***********************************************************************************");
      System.out.println("Write a program to play the pig game against the computer. At each turn, the current player will");
      System.out.println("roll a pair of dice and accumulates points. The goal is to reach to 100 or more points before your");
      System.out.println("opponent does. (For the testing purposes use 30 instead of 100 points) If, on any turn, the player");
      System.out.println("rolls a 1, all the points accumulated for that round are forfeited and the control of the dice");
      System.out.println("moves to the other player. If the player rolls two 1s in one turn, the player loses all the points");
      System.out.println("accumulated thus far are forfeited and the control moves to the other player. The player may");
      System.out.println("voluntarily turn over the control of the dice after each roll. Therefore player must decide to roll");
      System.out.println("again (be a pig) and risk losing points, or relinquish control of the dice, possibly allowing the");
      System.out.println("other player to win. Computer is going to flip a coin to choose the first player");
      System.out.println("***********************************************************************************");
      System.out.println("lets start the fun");
   }
   //flips a coin and decides who starts the game
   public static String flipCoin(Random rand)
   {
      int coin = rand.nextInt(2);
      String comp = "";
      switch (coin)
      {
         case 0: comp = "heads";
                 break;
         case 1: comp = "tails";   
                 break;
      }
      return comp;
   }
   public static int rollDice(Random rand)
   {
      int dice1 = rand.nextInt(6)+1;
      int dice2 = rand.nextInt(6)+1;
      System.out.println("Dice 1: " +dice1);
      System.out.println("Dice 2: " +dice2);
      return dice1+dice2;     
   }
   // select a random name of the computer via arrays
   public static String nameComputer(Random rand)
   {
      int name = rand.nextInt(10);
      String compName = "";
      switch (name)
      {
         case 0: compName = "Lisa";
                 break;
         case 1: compName = "Kathy";
                 break;
         case 2: compName = "Hali";
                 break;
         case 3: compName = "Jack";
                 break;
         case 4: compName = "Alex";
                 break;
         case 5: compName = "Max";
                 break;
         case 6: compName = "Jill";
                 break;
         case 7: compName = "James";
                 break;
         case 8: compName = "Martha";
                 break;
         case 9: compName = "Lauren";
                 break;
      }
      return compName;
   }
   public static void play(Random rand, Scanner input)
   {
      int playerScores = 0;
      int playerTotal = 0;
      int computerScores = 0;
      int computerTotal = 0;
      boolean gameOver = false
      boolean turnOver = false
      description();
      String compName = nameComputer(rand);
      System.out.println("Hi my name is " + compName);
      System.out.print("What is your name? ");
      String name = input.nextLine();
      System.out.println("Hi " + name + ", I am flipping the coin to determine who goes first");
      System.out.print("press any key to start the game. ");
     input.nextLine(); 
     String flip = flipCoin(rand);
     int turn;
     if (flip.equals("heads"))
     {
        turn = 1;
        System.out.println("You are going to start the game");
     }
     else
     {
        turn = 0;
        System.out.println(compName + " is going to start the game");
     } 
   }
}

Answer 1

创建：

处理游戏转弯（掷骰子，计算点等）的playTurn(int turn)功能（玩家为1，计算机为0）
一个布尔函数，检查是否有赢家。示例：isWinner（int player）（再次，1表示播放器，0表示计算机）

首次在您的if() else声明中使用此功能：

if (flip.equals("heads"))
{
    turn = 1;
    System.out.println("You are going to start the game");
    playTurn(turn);
 }
 else
 {
    turn = 0;
    System.out.println(compName + " is going to start the game");
    playTurn(turn);
 }

然后你可以添加：

 do {
     if(turn == 1){
         turn = 0;
         playTurn(turn);
     }else{
         turn == 1;
         playTurn(turn);
     }
  while ( !isWinner(1)|| !isWinner(0) );

设计不是很好，但希望能为您提供下一步操作的提示。

Java骰子游戏 - 选择谁基于掷骰子和轮流开始游戏

1 个答案: