Question

我需要制作一个程序：重复滚动3个骰子，直到双打滚动（任何两个是相同的）。每次显示值，然后显示获得双打所需的尝试次数。

问题在于它是永远存在的，并不能准确地告诉我它运行了多少次。

这是我到目前为止所拥有的。

public class ExtraProblem4 {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        int first, second, third;
        int counter = 0;
        while(true) {
            counter ++;

            first = (int)(Math.random()*(6-1+1)+1);
            second = (int)(Math.random()*(6-1+1)+1);
            third = (int)(Math.random()*(6-1+1)+1);

            System.out.println(first + "\t" + second + "\t" + third + "\t");

            if (first == second || second == third || first == third) {
                System.out.println("Double! It took " + counter + " tries to get it!");
            }
            else {
                first = (int)(Math.random()*(6-1+1)+1);
                second = (int)(Math.random()*(6-1+1)+1);
                third = (int)(Math.random()*(6-1+1)+1);

                System.out.println(first + "\t" + second + "\t" + third + "\t");
            }
        }   

    }

Answer 1

你可能最好使用do-while而且..我也摆脱了一些冗余的代码行，比如if中的else。

public class ExtraProblem4 
{

    public static void main(String[] args)
    {
        // TODO Auto-generated method stub
        int first, second, third;
        int counter = 0;
        boolean rolledDoubles; //initializes boolean variable to keep the loop going
        do //use a do-while so it tests after each roll
        {
            rolledDoubles = false; //defines variable as false so it keeps looping
            counter = counter + 1; // more reliable step

            first = (int)(Math.random()*(6-1+1)+1);
            second = (int)(Math.random()*(6-1+1)+1);
            third = (int)(Math.random()*(6-1+1)+1);

            System.out.println(first + "\t" + second + "\t" + third + "\t");

            if (first == second || second == third || first == third) 
            {
                rolledDoubles = true; //you rolled a double! This will stop the loop
                System.out.println("Double! It took " + counter + " tries to get it!");
            }

        }
        while(!rolledDoubles); //uses not operator with rolledDoubles so when rolledDoubles is true then we stop the loop, if false we keep going
    }   

}

Answer 2

   public class ExtraProblem4 {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        int first, second, third;
        int counter = 0;
        boolean isDoubles= false;
        while (!isDoubles)
        {
            first = (int)(Math.random()*(6-1+1)+1);
            second = (int)(Math.random()*(6-1+1)+1);
            third = (int)(Math.random()*(6-1+1)+1);

            System.out.println(first + "\t" + second + "\t" + third + "\t");
            isDoubles= first == second || first == third || second == third;  
            counter++; 
        }       
        System.out.println("Double! It took " + counter + " tries to get it!");
      }
   }

Eclipse Java循环骰子滚动获取双打并显示它运行的次数

2 个答案: