Question

您好我正在为我的网站做点什么，当我添加一个功能时，我做了一个错误所以，如果你能帮助我找到它。错误是打开的）; 问题在于功能（呃，ro））; - ＆GT; ）;

pool.query('UPDATE games SET psteamid = "", pname = "", pavatar = "", pskinsurl = "", pskinsnames = "", pskinsprices = "", pskins = "", ptp = "", passetids = "", trade_token = "" WHERE id = ' + pool.escape(removefromGame[k]['id']), function(er, ro));

我试图解决它，但我找不到错误我试图删除）但没有..

Answer 1

试试这个：

pool.query('UPDATE games SET psteamid = "", pname = "", pavatar = "", pskinsurl = "", pskinsnames = "", pskinsprices = "", pskins = "", ptp = "", passetids = "", trade_token = "" WHERE id = ' + pool.escape(removefromGame[k]['id']), function(er, ro) {
    //do stuff with args er and ro
});

(er, ro)函数是pool.escape()的回调。您需要添加一个正文才能工作。

节点脚本上的意外令牌

1 个答案: