Question

我使用以下查询在新列中生成百分比，但我只想要两位小数。

    SELECT 
count( *) TestCount
,count(case when result_status = 'Not A Finding' then 1 end) TestPassedCount
,count(case when result_status = 'Not A Finding' then 1 end) / count(*) ThePercentage
,asset 
 FROM Table_Name
 group by asset

当前输出：

             TestCount  TestPassedCount    Percentage   Asset
                 18             7          0.388888889  DB2MOTIV:DBMOTIVA@mxemch010405ads.mx.hsbc

必需输出：

             TestCount  TestPassedCount    Percentage   Asset
                 18             7              38.89    DB2MOTIV:DBMOTIVA@mxemch010405ads.mx.hsbc

此致

Bharath Vikas

Answer 1

假设这是您想要实现的目标，只需将结果乘以100并添加round函数：

SELECT 
 count( *) TestCount
 ,count(case when result_status = 'Not A Finding' then 1 end) TestPassedCount
 ,round((count(case when result_status = 'Not A Finding' then 1 end) / count(*)) * 100,2) ThePercentage
 ,asset 
FROM 
 Table_Name
group by 
 asset

Answer 2

使用ROUND方法

android:supportsRtl

Answer 3

试试这个：

 Round(  count(case when result_status = 'Not A Finding' then 1 end) / count(*) * 100 , 2) ThePercentage

只需要两个十进制值百分比

3 个答案: