Question

我将日期存储在数组中，但是以特殊格式定义日期范围，如下所示：

Array
(
    [0] => Array
        (
            [0] => Array ///date start
                (
                    [0] => 2017
                    [1] => 10 //month
                    [2] => 3 //day
                )

            [1] => Array //date end
                (
                    [0] => 2017
                    [1] => 10 //month
                    [2] => 5 //day
                )

        )

    [1] => Array
        (
            [0] => Array //date start
                (
                    [0] => 2017
                    [1] => 11
                    [2] => 23
                )

            [1] => Array //date end
                (
                    [0] => 2017
                    [1] => 11
                    [2] => 25
                )

        )

)

如果数组中存在特定的字符串日期，我需要一个可以返回的函数

2017-10-01. is_in_array ('2017-10-01').

但我不明白如何处理foreach和日期范围的特殊数组格式。

Answer 1

试试这个

$arr = array(

    [
        [2017,10,3],
        [2017,10,5]
    ],
    [
        [2017,11,23],
        [2017,11,25]
    ],
    [
        [2017,12,1],
        [2017,12,10]
    ]

);

function is_in_array($array, $date) {
    $timestamp = strtotime($date);
    $date = date('d',$timestamp);
    $month = date('m',$timestamp);
    $year = date('Y',$timestamp);
    foreach ($array as $key => $value) {
        foreach($value as $value2) {
            if($value2[0]==$year && $value2[1] == $month && $date == $value2[2])
                return true;
        }
    }
    return false;
}

此处is_in_array()的第一个参数是您要查找日期的数组第二个参数是您要查找的日期。因此

is_in_array('2017-12-1'); //will return true
is_in_array('2017-5-2'); //will return false

Answer 2

试试这个：

$rangesArr = [
    [[2017, 10,  3], [2017, 10,  5]],
    [[2017, 11, 23], [2017, 11, 25]],
];

function is_in_array ($date) {
    global $rangesArr;
    $dateUnix = strtotime($date);
    foreach ($rangesArr as $range) {
        $rangeStartUnix = strtotime("{$range[0][0]}-{$range[0][1]}-{$range[0][2]}");
        $rangeEndUnix   = strtotime("{$range[1][0]}-{$range[1][1]}-{$range[1][2]}");
        if ($dateUnix >= $rangeStartUnix && $dateUnix < $rangeEndUnix) {
            return true;
        }
    }
    return false;
}

var_dump(is_in_array('2017-10-04')); // Returns true.
var_dump(is_in_array('2017-10-05')); // Returns false.

输出：

bool(true)
bool(false)

基本上，它只是遍历数组，将子范围的开始和结束数组转换为unix时间戳，并将其与传入日期的unix时间戳进行比较。

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Answer 3

如果您需要时间，可以尝试使用此变体

<?php
$discountDatesArr = [
    [[2018, 8,  5, '00:00:00'], [2018, 8,  9, '23:59:59']],
    [[2018, 8,  15, '00:00:00'], [2018, 8,  15, '23:59:59']],
    [[2018, 8,  19, '00:00:00'], [2018, 8,  19, '23:59:59']],
    [[2018, 8,  22, '00:00:00'], [2018, 8,  22, '23:59:59']],
    [[2018, 8,  29, '00:00:00'], [2018, 8,  29, '23:59:59']],
];

$isDiscountSystemActive = false;
$dateUnix = strtotime(date("Y-n-j H:i:s"));
foreach ($discountDatesArr as $range) {
    $rangeStartUnix = strtotime("{$range[0][0]}-{$range[0][1]}-{$range[0][2]} {$range[0][3]}");
    $rangeEndUnix   = strtotime("{$range[1][0]}-{$range[1][1]}-{$range[1][2]} {$range[1][3]}");
    if ($dateUnix >= $rangeStartUnix && $dateUnix < $rangeEndUnix) {
        $isDiscountSystemActive = true;
    }
}
define ("ISDISCOUNTACTIVE", $isDiscountSystemActive);
echo ISDISCOUNTACTIVE;

https://eval.in/1044922

在PHP中查找数组中的日期值

3 个答案: