如何按两(1)个不同的值对数组进行排序?
所以我有一个像这样的数组:
array(
array(
'id' => 10,
'total' => 38,
'entry' => 400
),
array(
'id' => 4,
'total' => 34,
'entry' => 3100
),
array(
'id' => 2,
'total' => 34,
'entry' => 3150
),
array(
'id' => 8,
'total' => 34,
'entry' => 2980
),
);
数组已按键total
排序,但它们在total
中的值都相同。所以我需要按entry
排序最接近3000的人。
修改
首先应该按total
然后entry
对数组进行排序,因为entry
只是在那里,所以我可以区分谁是最好的。
所以数组应如下所示:
array(
array(
'id' => 10,
'total' => 38,
'entry' => 400
),
array(
'id' => 8,
'total' => 34,
'entry' => 2980
),
array(
'id' => 4,
'total' => 34,
'entry' => 3100
),
array(
'id' => 2,
'total' => 34,
'entry' => 3150
)
);
答案 0 :(得分:2)
试试这个:
usort($arr, function ($a, $b) {
if ($a['total'] == $b['total']) { // Only compare on entry when the totals are the same.
return abs($a['entry'] - 3000) > abs($b['entry'] - 3000);
}
return $a['total'] < $b['total'];
});
print_r($arr);
输出:
Array
(
[0] => Array
(
[id] => 2
[total] => 35
[entry] => 3150
)
[1] => Array
(
[id] => 8
[total] => 34
[entry] => 2980
)
[2] => Array
(
[id] => 4
[total] => 34
[entry] => 3100
)
[3] => Array
(
[id] => 6
[total] => 34
[entry] => 3250
)
[4] => Array
(
[id] => 3
[total] => 32
[entry] => 3400
)
)
以下是它的工作原理:它会比较total
s,但如果它们相同,则会比较entry
和entry
之间的差值的绝对值