我使用新的Swift 4 Codable接口从Web服务中简单地获取JSON数据。我试图实现泛型类型方法来处理解码(所以我不需要自定义方法)但我一直收到错误。这是代码
extension StarWarsAPI {
public func decodeJson<T: Codable>(fetchUrl: URL, modelType: T, completion: @escaping (_ modelObject: Codable?, _ error:StarWarsErrorType?) -> Void){
//guard modelType is Codable else {return completion(nil,nil)}
var fetchRequest = URLRequest(url: fetchUrl, cachePolicy: .useProtocolCachePolicy, timeoutInterval: 10.0)
fetchRequest.httpMethod = "GET"
fetchRequest.allHTTPHeaderFields = [
"content-type": "application/json",
"cache-control": "no-cache",
]
let session = URLSession.shared
let fetchDataTask = session.dataTask(with: fetchRequest) { (data, response, error) in
guard error == nil else {
return completion(nil, StarWarsErrorType.urlResponseError(error: error))
}
guard let httpResponse = response as? HTTPURLResponse else {
return completion(nil, StarWarsErrorType.NilUrlResponseError())
}
guard let data = data else {
return completion(nil, StarWarsErrorType.noDataFound)
}
guard httpResponse.statusCode > 199 && httpResponse.statusCode < 300 else {
return completion(nil, StarWarsErrorType.httpErrorCode(code: httpResponse.statusCode))
}
var modelObject:Codable?
do {
let jsonDecoder = JSONDecoder()
modelObject = try jsonDecoder.decode(modelType.self, from: data)
return completion(modelObject, nil)
}catch{ // do nothing }
DispatchQueue.main.async {
completion(nil, nil)
}
}
}
fetchDataTask.resume()
}
错误读取&#34;无法调用&#39;解码&#39;使用类型&#39;(T,from:Data)的参数列表&#39;&#34; 。这是错误的屏幕截图。
我错过了什么?谢谢!
答案 0 :(得分:2)
传递给decode(_:from:)
的类型需要静态知道。 modelType.self
是modelType
的动态实例,但其类型不受静态约束;您需要使用T.self
,这是一种静态类型。