Python在ascii和hex

Question

我尝试在ascii中混合的字符串中查找消息，其格式如下：

"212zp*    ���                �91238902Pressure_1,9472,Pressure_2,4251,is_usb: {0}478212zp+    ���                �91238902Pressure_1,9472,Pressure_2,4251,is_usb: {0}478212zp,    ���                �91238902Pressure_1,9472,Pressure_2,4251,is_usb: {0}478212zp-    ���               "

我需要解码hex和ascii消息。消息介于91238902和478212

之间

我怎样才能做到这一点？该字符串是动态的，可以包含未定义数量的邮件，也可能会出现标题91238902和478212中的错误

Answer 1

这似乎是正则表达式的完美用法。这是指向pythex的链接：

import re
x = "212zp*91238902Pressure_1,9472,Pressure_2,4251,is_usb:{0}478212zp+91238902Pressure_1,9472,Pressure_2,4251,is_usb: {0}478212zp,91238902Pressure_1,9472,Pressure_2,4251,is_usb: {0}478212zp-"

# will grab between 91238902 and 478212
# alternative regex is: (?<=91238902).*?(?=478212)
result = re.findall(r'91238902(.*?)478212', x)

输出是一个列表：

['Pressure_1,9472,Pressure_2,4251,is_usb:{0}', 'Pressure_1,9472,Pressure_2,4251,is_usb: {0}', 'Pressure_1,9472,Pressure_2,4251,is_usb: {0}']