函数调用另一个在django shell中不起作用的函数

时间:2017-11-02 11:25:02

标签: python django python-3.x django-shell

我有一个文件:

def fetchArticles(topic):
    testing()
def testing():
    print("testing")
print("starting")
fetchArticles("World")

它存在于django中的应用程序中,当我使用python3 xyz.py将其作为独立文件运行时,它运行完全正常但是当我使用python3 manage.py shell< django shell运行它时xyz.py它无法找到测试功能。

显示此错误:

starting
Traceback (most recent call last):
  File "manage.py", line 22, in <module>
    execute_from_command_line(sys.argv)
  File "/usr/local/lib/python3.5/dist-packages/django/core/management/__init__.py", line 363, in execute_from_command_line
    utility.execute()
  File "/usr/local/lib/python3.5/dist-packages/django/core/management/__init__.py", line 355, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/usr/local/lib/python3.5/dist-packages/django/core/management/base.py", line 283, in run_from_argv
    self.execute(*args, **cmd_options)
  File "/usr/local/lib/python3.5/dist-packages/django/core/management/base.py", line 330, in execute
    output = self.handle(*args, **options)
  File "/usr/local/lib/python3.5/dist-packages/django/core/management/commands/shell.py", line 101, in handle
    exec(sys.stdin.read())
  File "<string>", line 12, in <module>
  File "<string>", line 4, in fetchArticles
NameError: name 'testing' is not defined

有人可以帮我解决这个问题吗?

0 个答案:

没有答案