Question

我有这些当前的结果

 PersonName Team    Daily Amount    Date
    Alex      4          10       2017-01-11
    Alex      4          10       2017-01-11
    Alex      4          10       2017-01-11
    Ben       1          10       2017-02-11
    Ben       1          10       2017-02-11
    Ben       1          10       2017-01-11
    Fred      3          10       2017-01-11
    Fred      3          10       2017-01-11
    Fred      3          10       2017-01-11
    Sam       2          10       2017-02-11
    Sam       2          10       2017-01-11
    Sam       2          10       2017-01-11
    Tom       2          10       2017-01-11
    Tom       2          10       2017-02-11
    Tom       2          10       2017-01-11

现在，我希望在两个单独的栏目中创建每日和每月的数字。

我正在寻找这样的结果：

 PersonName Team    Daily Amount    Date        Monthly Figure
    Alex      4          30       2017-01-11      30
    Ben       1          10       2017-01-11      30
    Fred      3          10       2017-01-11      30
    Sam       2          20       2017-01-11      30
    Tom       2          20       2017-01-11      30

到目前为止，我有这样的查询，但我不确定这是最好的方法。它给了我不同的分组总和结果比我预期的。

SELECT P.PersonName, min(P.Team) AS [Team],
SUM(F.Amount) AS [Daily Amount], min(F.Date) AS [Date], MTD.[Month To Date]
FROM Person P
JOIN Figure F on P.PersonID =F.PersonFK
WHERE DATEDIFF( d, F.Date, GETDATE() ) = 1 
GROUP BY P.PersonName


JOIN 
(SELECT 
P.PersonName, min(P.Team) AS [Team],
SUM(F.Amount) AS [Month To Date]
, min(F.Date) AS [Date]
FROM Person P
JOIN Figure F on P.PersonID =F.PersonFK
F.Date BETWEEN CAST(MONTH(GETDATE()) 
AS VARCHAR) + '/' + '01/' +  + CAST(YEAR(GETDATE()) AS VARCHAR)
AND  GETDATE() 
GROUP BY P.PersonName ) MTD
ON MTD.PersonName = P.PersonName

我已尝试过连接子查询以及使用联合但我无法得到我想要的结果。任何人都可以进一步建议我吗？感谢

SQL FIDDLE - http://sqlfiddle.com/#!6/23bbb/12

Answer 1

如果我理解正确，您希望找到每个人在特定日期支出的金额，并将其与该月的金额进行比较

declare @day date = '01-11-17'

select P.PersonName, 
    P.Team AS [Team],
   sum(case when date = @day then f.amount end) AS [daily amount] ,
   @day AS [Date],   
   sum(F.Amount) AS [monthly amount] 
from Person P
join Figure F on P.PersonID =F.PersonFK
where month(F.date) = month(@day)
group by P.PersonName, P.Team

demo

日/月过滤子查询

1 个答案: