Question

我正在尝试NOT IN选择NOT IN列表是动态的。像

这样的东西

SELECT id, type FROM CONTACTS where type NOT IN ('connect','answer')

在代码中，我徒劳无功的尝试是：

db.query(TABLE, new String[] { "id", ""}, " type NOT IN (?)", "connect,answer", 
    null, null, null); // didn't work
db.query(TABLE, new String[] { "id", ""}, " type NOT IN (?)", "'connect','answer'", 
null, null, null); // didn't work

我对此的看法是?替换将我的逗号列表视为单个参数。我确实找到了一个解决方案，但它相当丑陋所以我不会在这里发布它，直到有人提出更优雅的东西

Answer 1

你不能只放一个'？'而不是值列表。因此，尝试参数化列表几乎没有什么好处。当然，可以创建2,4,16值准备语句..." type NOT IN (?,?)", new String[]{ "connect","answer" },...，但即使在具有远程RDBMS的服务器上，它也具有可疑价值。相反，做

db.query(TABLE, new String[] { "id", ""}, " type NOT IN ('connect','answer')", 
     null, null, null, null);

如果列表是动态的，则必须转义字符串并将它们放入单引号列表中。

Answer 2

您可以使用String.format动态设置参数。

例如：

db.query(TABLE, new String[] { "id", ""}, " type NOT IN (?)", "connect,answer", null, null, null);

=＆GT;

String argsArrayToString(List<String> args) {
    StringBuilder argsBuilder = new StringBuilder();
    argsBuilder.append("(");
    final int argsCount = args.size();
    for (int i=0; i<argsCount; i++) {
        argsBuilder.append(args.get(i));
        if (i < argsCount - 1) {
            argsBuilder.append(",");
        }
    }
    argsBuilder.append(")");
}

db.query(TABLE, new String[] { "id", ""}, String.format(" type NOT IN (%s)", argsArrayToString(arrays)), null, null, null, null);

Answer 3

如果动态创建包含“not in”值列表的String，然后将它们附加到sql字符串的末尾，可以动态使用“not in”，如下所示：

public static Vector selectAllFormTypesForAccountIgnoringFormVersions(
        int accountId, String formsIgnored) {
protected final static String selectAllFormTypesForAccountIgnoringFormVersions = "SELECT DISTINCT FormType.*"
        + " FROM FormType, Form WHERE Form.accountId=? AND FormType.formTypeContentId = Form.formTypeContentId"
        + " AND Form.formVersionId NOT IN (";

    Vector allFormTypes = new Vector();
    SQLiteDatabase db = null;
    String[] selectionArgs = { Integer.toString(accountId)};

    try {
        DataManager_Platform dataManager = (DataManager_Platform) DataManager_Platform
                .getDataManager();
        db = (SQLiteDatabase) dataManager.getDatabase();
        Cursor cursor = db.rawQuery(
                selectAllFormTypesForAccountIgnoringFormVersions + formsIgnored + ")",
                selectionArgs);

        if (cursor.getCount() > 0) {
            cursor.moveToFirst();
            while (!cursor.isAfterLast()) {
                FormType_Platform formType = new FormType_Platform();
                formType.populateModel(cursor);
                allFormTypes.add(formType);
                cursor.moveToNext();
            }
        }
    } catch (Exception e) {
        System.out.println("Error: " + e.getMessage());
        e.printStackTrace();
    } finally {
        try {
            if (db != null) {
                db.close();
            }
        } catch (Exception e) {
            System.out.println("Error: " + e.getMessage());
            e.printStackTrace();
        }
    }

    return allFormTypes;
}

Android Sqlite IN，NOT IN语法

3 个答案: