有一个List,我想创建books对象并将所有book对象添加到此List中。在这里,我采用了这样的正常方式。
public static List<Books> listOfBooks = new ArrayList<>();
public static void addProduct() {
Books book1 = new Books("java", "games", 200.56);
Books book2 = new Books("c", "dennis", 300.56);
Books book3 = new Books("c++", "Bjarne", 250.56);
Books book4 = new Books("javaScript", "Brendan", 209.56);
Books book5 = new Books("Sql", "Donald", 249.56);
listOfBooks.add(book1);
listOfBooks.add(book2);
listOfBooks.add(book3);
listOfBooks.add(book4);
listOfBooks.add(book5);
}
我想通过使用lamda表达式进行相同的操作,但我不知道该怎么做。请帮帮我吗?
答案 0 :(得分:1)
你可以写:
List<String> mylist = new Arraylist<>(Collections.nCopies("4.5",count));
使用方法引用而不是lambda来缩短:
Arrays.asList(book1, book2, ...).forEach(b -> listOfBooks.add(b));
但这并不比写作好:
Arrays.asList(book1, book2, ...).forEach(listOfBooks::add);
答案 1 :(得分:0)
Stream
API正在使用lambda表达式,但不属于它。
public static List<Books> listOfBooks = new ArrayList<>();
public static void addProduct() {
String[] languages = {"java", "c", "c++", "javascript", "Sql"};
String[] authors = {"games", "dennis", "Bjarne", "Brendan", "Donald"};
double[] prices = {200.56d, 300.56d, 250.56d, 209.56d, 249.56d};
listOfBooks = IntStream.range(0, languages.length)
.mapToObj(i -> new Books(languages[i], authors[i], prices[i]))
.collect(Collectors.toList());
// Alternatively:
/* IntStream.range(0, languages.length)
.mapToObj(i -> new Books(languages[i], authors[i], prices[i]))
.forEach(listOfBooks::add);
*/
}